A 2.44×104-kg rocket blasts off vertically from the earth's surface with a constant acceleration. During the motion considered i
1 answer:
Answer:
x = 2381.2 m , t = 14.43 s , I = 8.05 10⁶ N s
Explanation:
a) to find the distance to break the sound barrier (v = 330 m / s) we use the kinematic relationship
v² = v₀² + 2 a x
To find the acceleration suppose the rocket does not break the wire that holds the load, so we can use the second Newton law to find the maximum acceleration
T = m a
a = T / m
Body mass and weight is related
W = mg
m = W / g
a = T g / W
a = 44.1 9.8 / 18.9
a = 22,867 m / s²
Let's look for the distance if part of the rest
x = v² / 2 a
x = 330² /(2 22,867)
x = 2381.2 m
.b) the time to break this barrier
v = v₀ + a t
t = v / a
t = 330 / 22,867
t = 14.43 s
c) the thrust is
I = Δp
I = m –m v₀
I = 2.44 10⁴ 330 -0
I = 8.05 10⁶ N s
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Answer:
Time = 80.91 seconds
Explanation:
Given the following data;
Velocity = 5.50 m/s.
Distance = 445 meters
To find the time;
Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.
Mathematically, velocity is given by the equation;
Substituting into the formula, we have;
5.5 = 445/time
Time = 445/5.5
Time = 80.91 seconds
Answer:
a) The average velocity is v = (60 km/h ; 0)
b) The average speed is 60 km/h
Explanation:
The velocity is a vector that has a magnitude and direction. The average speed is the distance traveled over time without taking into account the direction of the motion.
a)The average velocity is calculated as the displacement over time:
v = Δx/Δt
where
v = velocity
Δx = final position - initial position = traveled distance relative to the center of the reference system.
Δt = final time - initial time (initial time is usually = 0)
We know that the displacement is 84 km but we do not know the time. It can be calculated from the two parts of the trip.
In part 1:
v = 45 km/h = 42 km / t
t = 0.93 h
In part 2:
v = 90 km/h = 42 km / t
t = 42 km / 90 km/h
t = 0.47 h
The time of travel is 0.47 h + 0.93 h = 1.4 h
The average velocity will be:
v = 84 km / 1.4 h = 60 km/h
Expressed as a vector in a 2-dimension plane:
v = (60 km/h; 0)
b) The average speed is calculated as the distance traveled over time. Note that in this case, the distance is equal to the displacement since the direction of the motion is always in one direction. But if the direction of the second part of the trip would have been the opposite to the direction of the first part, the displacement would have been 0 (final position - initial position = 0, because final position = initial position), then, the average velocity would have been 0. In change, the average speed would have been the distance traveled (84 km, 42 km in one direction and 42 km in the other) over time.
Then:
average speed = 84 km / 1.4 h = 60 km/h
c) see attached figure.
Explanation:
Given that,
Number of sodium ions at the negative electrode,
Number of chloride ions at the positive electrode,
(a) The current flowing in the circuit is due to the positive as well as negative charges such that total charge becomes:
Q = 0.01056 C
The current is given by :
So, the current passing between the electrodes is 10.56 mA.
(b) The direction of electric current is towards negative electrodes.