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juin [17]
3 years ago
5

The heat of solution with calcium chloride is endothermic what will happen to the temperature of the container/flask when calciu

m chloride is added to water in the container/flask
Chemistry
2 answers:
tino4ka555 [31]3 years ago
6 0
Endothermic means it absorb energy from surrounding and its sign is positive so when it absorb this energy the flask or the container become colder 
Anna [14]3 years ago
6 0

Answer: the temperature of the container/flask will decrease.


Justification:


1) As stated in the question, the heat of the solution is endothermic.


Endothermic is a process (physical or chemical) in which energy is absorbed from the surroundings by the initial substances to end in the final state.


2) The fact of absorbing heat energy will translate in the decrease of temperature of the surroundings, in this case the container/flask.

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<span><u><em>Answer:</em></u>
combustion reaction

<u><em>Explanation:</em></u>
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5 0
3 years ago
Read 2 more answers
What would be the molarity of a solution in which 0.56 mole of NaCl is dissolved in enough water to make 2.7 L of solution?
yan [13]

Answer:

Molarity = 0.21 M

Explanation:

Moles <em>solute </em>(mol) = Volume <em>solution</em> (L) x Molarity <em>solution </em>(M)

0.56 mol NaCl = 2.7 L x M

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5 0
2 years ago
Consider the reaction. 2 HBr(g) ¡ H2(g) + Br2(g) a. Express the rate of the reaction in terms of the change in concentration of
Studentka2010 [4]

Answer :

(A) The rate expression will be:

Rate=-\frac{1}{2}\frac{d[HBr]}{dt}=+\frac{d[H_2]}{dt}=+\frac{d[Br_2]}{dt}

(B) The average rate of the reaction during this time interval is, 0.00176 M/s

(C) The amount of Br₂ (in moles) formed is, 0.0396 mol

Explanation :

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The given rate of reaction is,

2HBr(g)\rightarrow H_2(g)+Br_2(g)

The expression for rate of reaction :

\text{Rate of disappearance of }HBr=-\frac{1}{2}\frac{d[HBr]}{dt}

\text{Rate of disappearance of }H_2=+\frac{d[H_2]}{dt}

\text{Rate of formation of }Br_2=+\frac{d[Br_2]}{dt}

<u>Part A:</u>

The rate expression will be:

Rate=-\frac{1}{2}\frac{d[HBr]}{dt}=+\frac{d[H_2]}{dt}=+\frac{d[Br_2]}{dt}

<u>Part B:</u>

\text{Average rate}=-\frac{1}{2}\frac{d[HBr]}{dt}

\text{Average rate}=-\frac{1}{2}\frac{(0.512-0.600)M}{(25.0-0.0)s}

\text{Average rate}=0.00176M/s

The average rate of the reaction during this time interval is, 0.00176 M/s

<u>Part C:</u>

As we are given that the volume of the reaction vessel is 1.50 L.

\frac{d[Br_2]}{dt}=0.00176M/s

\frac{d[Br_2]}{15.0s}=0.00176M/s

[Br_2]=0.00176M/s\times 15.0s

[Br_2]=0.0264M

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\text{Moles of }Br_2=\text{Concentration of }Br_2\times \text{Volume of solution}

\text{Moles of }Br_2=0.0264M\times 1.50L

\text{Moles of }Br_2=0.0396mol

The amount of Br₂ (in moles) formed is, 0.0396 mol

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Answer:

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