A typical compact car experiences a total drag force at 55 m i/h of about 350 N. If this car gets 35 miles per gallon of gasolin
1 answer:
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G = 9.81 m/sec^2) g = 9.81
<span>Solving for velocity : </span>
<span> = 2gh </span>
<span>v = </span>
<span>v = (2 x 9.81 x 10)^1/2 </span>
<span>v = 196.2 m/sec (answer)</span>
<span>Solving for velocity : </span>
<span>v = </span>
<span>v = (2 x 9.81 x 10)^1/2 </span>
<span>v = 196.2 m/sec (answer)</span>
Answer:
a) Image attached
b) It is acting CW
c) τ = 0.294N.m
Explanation:
As you can see in the image, the ruler will rotate clockwise.
For the total torque: τ = -W*(0.5 - 0.35) The distance used is from 35cm to 50cm
τ = -0.294N.m The magnitude is therefore: 0.294N
