Answer:
45.3°C
Explanation:
Heat gained = mass × specific heat × increase in temperature
q = mC (T − T₀)
Given C = 0.128 J/g/°C, m = 94.0 g, q = 305 J, and T₀ = 20.0°C:
305 J = (94.0 g) (0.128 J/g/°C) (T − 20.0°C)
T = 45.3°C
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Answer:
Explanation:
We shall represent each displacement in vector form .
i will represent east , j will represent north .
D₁ = 4.1 west = - 4.1 i
D₂ = 17.3 north = 17.3 j
D₃ = - 1.2 cos65.4 i + 1.2 sin65.4 j
= - .5 i + 1.09 j
Total displacement
= D₁ + D₂ + D₃
= - 4.1 i + 17.3 j - .5 i + 1.09 j
D = - 4.6 i + 18.39 j
magnitude of D
= √ ( 4.6² + 18.39² )
= √ (21.16 + 338.2 )
= √359.36
= 18.95 km .
Final displacement = 18.95 km .
The formula we can use in this case is:
d = v0t + 0.5 at^2
v = at + v0
where,
d = distance travelled
v0 = initial velocity = 0 since at rest
t = time travelled
a = acceleration
v = final velocity when it took off
a. d = 0 + 0.5 * 3 * 30^2
d = 1350 m
b. v = 3 * 30 + 0
<span>v = 90 m/s</span>
Answer:
1.5 × 10^11 meters
Explanation:
the distance of the Earth to the Sun is 1.5 × 10^11meters