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OlgaM077 [116]
3 years ago
10

Please help I need the awnser quick will give brain to first to awnser

Chemistry
2 answers:
gizmo_the_mogwai [7]3 years ago
7 0
Possibly decomposition but not sure
Bess [88]3 years ago
3 0
It’s decomposition. Please give brainliest if that’s correct
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Suppose you carry out a titration involving 2.50 molar NaOH and an unknown concentration of HBr. To bring the reaction to its en
givi [52]

Answer:

B

Explanation:

Brainly Patrol ima stop you here

7 0
2 years ago
Help me please!!!( ꈍᴗꈍ)​
Dahasolnce [82]

Answer:

<h3>Which of the following increases with the increase in the temperature in case of a liquid?</h3><h2><em>Va</em><em>pour</em><em> </em><em> </em><em>Pressure</em><em> </em></h2>

Explanation:

When a closed container contains liquid, higher the temperature, higher the evaporation the evaporation will be.

So Vapour Pressure should be the correct answer.

6 0
2 years ago
Read 2 more answers
How many total atoms are in 0.680 g of P₂O5?
Ludmilka [50]

Answer: 2.88×10^{24}atoms P_{2}O_{5}

Explanation: First, using stoichiometry, we must convert this from grams to moles, then from moles to atoms.

1. For the first step, we should also look at the periodic table to find the molar mass of the compound, then use that as the denominator.

0.680g P_{2} O_{5} *\frac{1molP_{2} O_{5} }{141.948gP_{2} O_{5} } =4.79mol P_{2} O_{5}

2. Now that it is converted to moles, we must convert it to atoms by multiplying it by Avogadro's number.

4.79molP_{2} O_{5} *\frac{6.022X10^{23} }{1mol} =2.88*10^{24}

With this information, we know that there are 2.88X10^{24} total atoms in 0.680 grams P_{2} O_{5}.

I hope this helps! Pls give brainliest!! :)

8 0
2 years ago
Name five solvents other than water​
vovikov84 [41]

Answer:

Ethanol

Methanol

Acetone

Tetrachloroethylene

and Hexanes

Explanation:

5 0
3 years ago
Before any reaction occurs, the concentration of A in the reaction below is 0.0510 M. What is the equilibrium constant if the co
Lilit [14]

Answer:

0.0119

Explanation:

There was a part missing. I think this is the whole question:

<em>Before any reaction occurs, the concentration of A in the reaction below is 0.0510 M. What is the equilibrium constant if the concentration of A at equilibrium is 0.0153 M?</em>

A (aq) ⇌ 2B (aq) + C(aq)

<em>Remember to use correct significant figures in your answer. Do not include units in your response.</em>

First, we have to make an ICE Chart, which stands for initial, change and equilibrium. We will call "x" unknown concentrations.

        A (aq) ⇌ 2B (aq) + C (aq)

I       0.0510       0            0

C         -x          +2x          +x

E    0.0510-x     2x            x

Since the concentration at equilibrium of A is 0.0153 M, we get

0.0510 - x = 0.0153 \\x = 0.0357

We can use the value of x to calculate the concentrations at equilibrium.

[A]e = 0.0153 M \\[B]e = 2x = 2(0.0357) = 0.0714 M \\[C]e = x = 0.0357 M \\

The equilibrium constant, Kc, is the ratio of the equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients.

Kc = \frac{[B]^{2}  \times [C]}{[A]} = \frac{0.0714^{2}  \times 0.0357}{0.0153} = 0.0119

The equilibrium constant for this reaction at equilibrium is 0.0119.

You can learn more about equilibrium here: brainly.com/question/4289021

7 0
2 years ago
Read 2 more answers
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