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4 years ago

Can u guys answer this and fast (3.610^2)(2.8*10^2)

1 answer:

7 0

so basically we only use the associative property of multiplication and one of the laws of exponents

associative=a(bc)=(ab)c
also law of exponent=a^x times a^y=a^(x+y)

(3.6 times 10^2) times (2.8 times 10^2)
associative
3.6 times 10^3 times 2.8 times 10^2
3.6 times 2.8 times 10^2 times 10^2
law of exponents
10^2 times 10^2=10^(2+2)=10^4
3.6 times 2.8=10.08
the answer is 10.08 times 10^4 or (10.08*10^4) or (1.001*10^5)

the second one


(3.6 times 10^6) times (2.2 times 10^-4)
associative
3.6 times 10^6 times 2.2 times 10^-4
3.6 times 2.2 times 10^6 times 10^-4
law of exponents
10^6 times 10^-4=10^(6-4)=10^2
3.6 times 2.2=7.92
the answer is 7.92 times 10^2 or (7.92*10^2)


A is (1.001*10^5)
 B is (7.92*10^2)

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Data given and notation

$\bar X=67$ represent the sample mean

$s=12$ represent the population standard deviation for the sample

$n=16$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 60, the system of hypothesis would be:

Null hypothesis: $\mu \leq 60$

Alternative hypothesis: $\mu > 60$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

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Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{67-60}{\frac{12}{\sqrt{16}}}=2.33$

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Can u guys answer this and fast (3.6*10^2)*(2.8*10^2)

Can u guys answer this and fast (3.610^2)(2.8*10^2)