Answer:
Hydrogen chloride (HCl), a compound of the elements hydrogen and chlorine, a gas at room temperature and pressure. A solution of the gas in water is called hydrochloric acid.
Explanation:
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Answer: Reducing agent in the given reaction is
.
Explanation:
A reducing agent is defined as an element which tends to lose electrons to other element leading to an increase in its oxidation number.
In the given reaction, oxidation state of sulfur in
is +2 and
has 0 oxidation state.
In
oxidation state of S is 2.5 and in
oxidation state of I is -1.
Since, an increase in oxidation state of S is occurring from +2 to +2.5. Hence, it is acting as a reducing agent.
Thus, we can conclude that reducing agent in the given reaction is
.
<u>Answer:</u>
<u>For a:</u> The chemical equation for the dissolution of sodium carbonate is 
<u>For b:</u> The net acid-base reaction is 
<u>Explanation:</u>
Dissolution reaction is defined as the reaction in which a solid compound gets dissolved in water to form aqueous solution.
The chemical equation for the dissolution of sodium carbonate follows:

Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.
The chemical equation for the ionization of sodium carbonate follows:

Now, the anion formed which is
reacts with water to form conjugate acid.
The chemical equation for the reaction of anion with water follows:

Hence, the net acid-base reaction of the anion formed and water is written above.
The specific heat capacity of the metal given the data from the question is 0.66 J/gºC
<h3>Data obtained from the question</h3>
- Mass of metal (M) = 76 g
- Temperature of metal (T) = 96 °C
- Mass of water (Mᵥᵥ) = 120 g
- Temperature of water (Tᵥᵥ) = 24.5 °C
- Equilibrium temperature (Tₑ) = 31 °C
- Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
- Specific heat capacity of metal (C) =?
<h3>How to determine the specific heat capacity of the metal</h3>
The specific heat capacity of the sample of the metal can be obtained as follow:
Heat loss = Heat gain
MC(M –Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)
76 × C × (96 – 31) = 120 × 4.184 × (31 – 24.5)
C × 4940 = 3263.52
Divide both side by 4940
C = 3263.52 / 4940
C = 0.66 J/gºC
Learn more about heat transfer:
brainly.com/question/6363778
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