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eimsori [14]
3 years ago
5

Chemistry

Chemistry
1 answer:
sukhopar [10]3 years ago
6 0

Answer:

11.442E23molecules

Explanation:

Given data:

Number of moles of water = 1.9 mol

Number of molecules of water = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

In 1.9 moles:

1.9 mol × 6.022 × 10²³ molecules / 1 mol

11.442 × 10²³ molecules

In e notation:

11.442E23 molecules

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A reaction vessel contains 10.0 g of CO and 10.0 g of O2. How many grams of CO2 could be produced according to the following rea
iren2701 [21]

Answer:

1. 15.71 g CO2

2. 38.19 % of efficiency

Explanation:

According to the balanced reaction (2 CO(g) + O2(g) → 2 CO2(g)), it is clear that the CO is the limitant reagent, because for every 2 moles of CO we are using only 1 mole of O2, so even if we have the same quantity for both reagents, not all of the O2 will be consumed. This means that we can just use the stoichiometric ratios of the CO and the CO2 to solve this question, and for that we need to convert the gram units into moles:

For CO:

C = 12.01 g/mol

O = 16 g/mol

CO = 28.01 g/mol

(10.0g CO) x (1 mol CO/28.01 g) = 0.3570 mol CO

For CO2:

C = 12.01 g/mol

O = 16 x 2 = 32 g/mol

CO2 = 44.01 g/mol

We now that for every 2 moles of CO we are going to get 2 moles of CO2, so we resolve as follows:

(0.3570 mol CO) x (2 mol CO2/2 mol CO) = 0.3570 moles CO2

We are obtaining 0.3570 moles of CO2 with the 10g of CO, now lets convert the CO2 moles into grams:

(0.3570 moles CO2) x (44.01 g/1 mol CO2) = 15.71 g CO2

Now for the efficiency question:

From the previous result, we know that if we produce 15.71 CO2 with all the 10g of CO used, we would have an efficiency of 100%. So to know what would that efficiency be if we would only produce 6g of CO2, we resolve as follows,

(6g / 15.71g) x 100 = 38.19 % of efficiency

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3 years ago
Give the correct balanced equation for the single replacement reaction of magnesium with aluminum oxide.
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<h3><u>Answer;</u></h3>

C. 3Mg + Al2O3 → 3MgO + 2Al

<h3><u>Explanation;</u></h3>
  • <u><em>Single replacement reaction is a type of reaction which one reactant reacts with another and makes a product by replacing one element by another. </em></u>
  • Mg (Magnesium) reacts with Al₂O₃ (Aluminium oxide) and produces MgO (Magnesium oxide) and Al (Aluminium) as products. Here Al is replaced by Mg. Reaction is 

            Mg + Al₂O₃ → MgO + Al

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The balanced equation will  be;

3Mg + Al2O3 → 3MgO + 2Al

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