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SCORPION-xisa [38]
3 years ago
14

Which of the following compounds exhibit hydrogen bonding?

Chemistry
1 answer:
hodyreva [135]3 years ago
7 0

Answer:

a,b,e,f,g

Explanation:

Hydrogen bonding is an intermolecular force of attraction between two molecules. It is a special type of dipole-dipole attraction.

In hydrogen bonding, the hydrogen on one molecule binds with an electronegative atom on another molecule usually oxygen, nitrogen and fluorine.

The simple electrostatic attraction leads to strong intermolecular interaction between two molecules.

 For the formation of hydrogen bond, a hydrogen atom must be bonded to more electronegative specie usually N, O and F

  In H₂O and H₂O₂ ;   hydrogen bonds with Oxygen

       CH₃NH₂; hydrogen is attached to nitrogen

       HF; hydrogen is attached to fluorine

        CH₃OH; hydrogen is attached to oxygen

         

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What mass in grams would 5.7L of hydrogen gas occupy at STP?​
tekilochka [14]

Answer:  The correct answer is:  " 0.54 g " .

__________________________________________

Explanation:

Note that "hydrogen gas" is:  

H₂ (g)  ;   that is:  a "diatomic element" (diatomic gas) ;

_________________________________________

The molecular weight of "H" is:  1.00794 g ;

   (From the Periodic Table of Elements).

So, the molecular weight of:  H₂ (g)  is:

    " 1.00794 g * 2  = 2.01588 g ; {use calculator) ;

_________________________________________

Note the conversion for a gas at STP:

______

  1 mol of a gas = 22.4 L gas;

___

i.e. " 1 mol / 22.4 L " ;

____

So:     " 5.7 L H₂ (g)  *  \frac{1 mol H_{2} }{22.4 L} *\frac{2.01588 g}{mol} =? ;

The "L" ("literes" cancel out to "1" ;  since "L/L = 1 ;

The "mol" (moles) cancel out to "1" ; since "mol/mol = 1 ;

____

and we are left with:

____

 [5.7 * 2.104588 g ] / 22.4  =  ?  g ;

______________________

→ [ 11.9961516  g ] / 22.4 =

          0.53554248214  g ;l

_____________________________

We round this value to:  " 0.54 g " ;

 → since "5.7 L " has 2 (two) significant figures;  

     22.4 is an exact number conversion;

     and "5.7 L" has fewer significant figures than:

    " 2.104588 " ; or:  " 1.00794 " .

  → as such: We round to "2 (two) significant figures."

______________________________

Hope this is helpful.  Wishing you the best in your academic endeavors!

_______________________________

8 0
3 years ago
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allochka39001 [22]
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4 0
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