Which of the following compounds exhibit hydrogen bonding?

Chemistry

1 answer:

hodyreva [135]3 years ago

7 0

Answer:

a,b,e,f,g

Explanation:

Hydrogen bonding is an intermolecular force of attraction between two molecules. It is a special type of dipole-dipole attraction.

In hydrogen bonding, the hydrogen on one molecule binds with an electronegative atom on another molecule usually oxygen, nitrogen and fluorine.

The simple electrostatic attraction leads to strong intermolecular interaction between two molecules.

For the formation of hydrogen bond, a hydrogen atom must be bonded to more electronegative specie usually N, O and F

In H₂O and H₂O₂ ; hydrogen bonds with Oxygen

CH₃NH₂; hydrogen is attached to nitrogen

HF; hydrogen is attached to fluorine

CH₃OH; hydrogen is attached to oxygen

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If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio

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Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

$n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2} =0.75molCd(OH)_2$

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

$m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2$