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pishuonlain [190]
2 years ago
15

What is the total anion concentration (in meq/l) of a solution that contains 6.0 meq/lna+ , 11.0 meq/lca2+ , and 3.0 meq/lli+ ?

Chemistry
2 answers:
Oliga [24]2 years ago
7 0
<span>Answer: The total anion concentration = 6.0 + 2x12.0 + 3.0 = 33.0mEq/L</span>
Evgen [1.6K]2 years ago
7 0

We know that each equivalent of Na+ will be combined with one equivalent of anion concentration

Each equivalent of Ca+2 will combine with one equivalent of anion

each equivalent of Li+ will combine with one equivalent of anion

As we are given with 6.0 meq/lna+ , 11.0 meq/lca2+ , and 3.0 meq/lli+ ?

So for each  6.0 meq/l  Na+, the anion concentration will be 6.0 meq/l

So for each  11 meq/l Ca+2 , the anion concentration will be 11meq/l

So for each  3.0 meq/l Li+ , the anion concentration will be 3 meq/l

Thus total anion concentration = 6 + 11 + 3 = 20 meq/l

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Answer:

204.73K

Explanation:

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So, if you plug it in, you will get:-

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hope this is correct!

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Answer:

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now 400 ml of NO × 2 mol of NO2/2 mol of NO

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6 0
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I need help asap thank u
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It is b, i learned this last year hope this helps
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