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3 years ago

The atomic number is equal to

1 answer:

3 0

1. “what forms of energy conversions occur during the process of photosynthesis? (How does energy transform?) 2. What is missing from the food web but is essential to maintain equilibrium? A. Soil B.water C. Decomposers D. Oxygen

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What is the formula mass of ferric sulphate, Fe2(SO4)3?

telo118 [61]

It would be 399.88 g/mol.

3 0

4 years ago

What is the concentration of acetic acid if three 65.0 mL samples of actic acid were neutralized with 16.8 mL, 18.2 mL, and 17.3

nydimaria [60]

M₁V₁=M₂V₂

65 x M₁ = 16.8 x 0.5

M₁ = 0.129

65 x M₁ = 18.2 x 0.5

M₁ = 0.14

65 x M₁ = 17.35 x 0.5

M₁ = 0.133

Average = 0.129 + 0.14 + 0.133 = 0.134 M

8 0

2 years ago

Is each of these statements true? If not, explain why.(e) If reactant molecules collide with greater energy than the activation

Natali5045456 [20]

If reactant molecules collide with greater energy than the activation energy, they change into product molecules is true.

<h3>What is activation energy?</h3>

The activation energy is the minimum amount of energy that is required to be absorbed or supplied to the reactant in the reaction to become their energy which is equal to the threshold energy.

The threshold energy depends on the molecule's decision which must be in order but must be an effective collision that is the minimum amount of energy needed for collision.

Therefore, the statement is true that reactant molecules collide with greater energy than the activation energy, they change into product molecules.

Learn more about activation energy, here:

brainly.com/question/20261559

#SPJ4

3 0

2 years ago

A quantity of water is heated from 25.0°C to 36.4°C by absorbing 325 J of heat energy. If the specific heat of water is 4.18 J /

Arlecino [84]

Answer:

6,8 g

Explanation:

c = 4.18 J/(g * °C) = 4180 J / (kg * °C)

$t_{1}$ = 25 °C

$t_{2}$ = 36,4 °C

Q = 325 J

The formula is: Q = c * m * ( $t_{2} - t_{1}$ )

m = $\frac{Q}{c * (t_{2} - t_{1} )}$

Calculating:

m = 325 / 4180 * (36,4 - 25) ≈ 0,0068 kg = 6,8 g

6 0

3 years ago

how much sugar can they create if 200 grams of carbon dioxide are used? 6 CO2 + 6 H2O right arrow C6H12O6 + 6 O2

zimovet [89]

So we know that the molar ration of carbon dioxide to sugar is 6:1 in the balanced equation, so we must first find how many moles of carbon dioxide 200g is.

The molar weight of carbon dioxide is 44.008g - found from the atomic weights of the elements on the periodic table.

So we must solve for moles:

$200g*\frac{1mol}{44.008g}=4.545mol$

So then we can set up a proportion to solve for how many moles of sugar were produced:

$\frac{1mol_{sugar}}{6mol_{CO_{2}}}= \frac{xmol_{sugar}}{4.545mol_{CO_{2}}}$

Then we solve for x:

$6x=4.545$

$x=0.7575$

So now we know that 0.7575 moles of sugar were produced. To convert to grams, we must know the molar weight of sugar:

$6(12.01g)+12(1.008g)+6(15.999g)=72.06g+12.096g+95.994g=180.15g$

So then we can solve for grams of sugar:

$\frac{180.15g}{1mol}*0.7575mol=136.46g_{sugar}$

Therefore we know you can make 136.46 grams of sugar when using 200 grams of carbon dioxide.

8 0

4 years ago