1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
V125BC [204]
3 years ago
14

Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3 (g). At equilibrium, th

e concentrations of the different species are as follows. [NH3] = 0.105 M [N2] = 1.1 M [H2] = 1.50 M
Chemistry
1 answer:
artcher [175]3 years ago
6 0

Answer:

The <u>equilibrium constant</u> is:

              k_c=0.0030M^{-2}

Explanation:

The correct equation is:

  •   N₂(g)    +    3H₂(g)    ⇄    2NH₃(g)

Thus, with the equilibrium concentrations you can calculate the equilibrium constant, Kc.

The equation for the equilibrium constant is:

         k_c=\dfrac{[NH_3]^2}{[N_2]\cdot [H_2]^3}

Substituting:

        k_c=\dfrac{(0.105M)^2}{(1.1M)\cdot (1.50M)^3}

         k_c=0.0030M^{-2}

You might be interested in
The voltage generated by the zinc concentration cell described by the line notation Zn ( s ) ∣ ∣ Zn 2 + ( aq , 0.100 M ) ∥ ∥ Zn
Oxana [17]

Answer:

0.193 M

Explanation:

We need to calculate the Zn²⁺ concentration at the cathode where reduction occurs which is the right side in the expression:

Zn2+(aq,0.100 M) ‖ Zn2+(aq,? M) | Zn(s)

Zn²⁺ (aq,?) + 2 e⁻   ⇒ Zn (s)

and oxidation will occur in the anode

Zn (s) ⇒ Zn²⁺ (aq, 0.100 M ) + 2 e⁻

and the overall reaction is

Zn²⁺ (aq,?) ⇒ Zn²⁺ (0.100 M )

The driving force is the difference in concentration and E the electromotive force will be given by

E = Eº - 0.0592/2 log [Zn²⁺ (0.100 M) / Zn²⁺ (M) ]

Plugging the value for E and knowing Eº is cero because we have the same electrodes, we have

17.0 x 10⁻³ = 0 - 0.0592 log 0.100/ X =

- 17.0 x 10⁻³ / 0.0592 = log 0.100 / X

- 0.287 = log (0.100 / X)

Taking inverse log to both sides of the equation

0.516 = 0.100 / X   ⇒ X = 0.100 / 0.516 = 0.193 M

4 0
3 years ago
Please help fast!!! What does the weight of an object depend on?
olga2289 [7]

weight depends on the force of gravity that is exerted on it.


3 0
3 years ago
Read 2 more answers
Chloroform flows through a 4.26 inch inside-diameter pipe at the rate of 3.60 gallons per minute. What is the average velocity o
Pani-rosa [81]

Answer:

1) 0,081 ft/s

2) 0,746 lb/s

Explanation:

The relation between flow and velocity of a fluid is given by:

Q=Av

where:

  • Q, flow [ft3/s]
  • A, cross section of the pipe [ft2]
  • v, velocity of the fluid [ft/s]

1)

To convert our data to appropiate units, we use the following convertion factors:

1 ft=12 inches

1 ft3=7,48 gallons

1 minute=60 seconds

So,

Q=\frac{3,60 gallons}{1 min}*\frac{1min}{60 s}*\frac{1ft3}{7,48gallons}=0,00802 \frac{ft3}{s}

As the pipe has a circular section, we use A=πd^2/4:

d=4,26 inch *\frac{1ft}{12 inch}=0,355ft\\  A=\pi \frac{0,355^{2} }{4}=0,0989ft2

Finally:

Q=vA......................v=Q/A

v=\frac{0,00802ft^{3} /s}{0,0989ft^{2} }=0,081ft/s

2)

The following formula is used to calculate the specific gravity of a material:

SG = ρ / ρW  

where:

  • SG = specific gravity,
  • ρ = density of the material [lb/ft3]
  • ρW = density of water [lb/ft3] = 62.4 lbs/ft3

then:

ρ = SG*ρW   = 1,49* 62,4 lb/ft3 = 93 lb/ft3

To calculate the mass flow, we just use the density of the chloroform in lb/ft3 to relate mass and volume:

0,00802 \frac{ft3}{s}*\frac{93lb}{1ft3}=0,746lb/s

7 0
3 years ago
If another student joins the game and stands behind the two students
Mandarinka [93]

Answer:

ha djd sidi dj sjejeisns

4 0
2 years ago
Milk of magnesia has the chemical formula Mg(OH)2. What is the mass of 3.2 moles of milk of magnesia? The molar Mass of magnesiu
GenaCL600 [577]
To calculate the mass of milk of magnesia given, we need certain data like molar mass of the compound which needs the atomic mass of the atoms in the compound. We calculate as follows:

Molar mass of <span>Mg(OH)2 = 24.3 g/mol + (2 x (16 + 1.0)) = 58.30 g/mol

Mass = 3.2 mol (</span>58.30 g/mol) = 186.56 grams
3 0
3 years ago
Other questions:
  • Given that the rate constant is 4.0×10−4 m−1 s−1 at 25.0 ∘c and that the rate constant is 2.6×10−3 m−1 s−1 at 42.4 ∘c, what is t
    11·1 answer
  • What is the empirical formula of the compound with the molecular formula c18h36?
    5·1 answer
  • Be sure to answer all parts. Radon (Rn) is the heaviest and the only radioactive member of Group 8A(18), the noble gases. It is
    14·1 answer
  • Substances which will glow in the dark after being exposed to sunlight are:
    15·1 answer
  • Help meeee!<br> 3874 dkg = _____ dg
    14·1 answer
  • At what points does the object accelerate please explain
    13·1 answer
  • Molecules that are too large to flow across the<br> membrane need help from what structures?
    15·2 answers
  • How many molecules of NO2 are in 0.36 moles?
    6·1 answer
  • Helppp plss
    11·1 answer
  • Which type of rock does B represent?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!