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Montano1993 [528]
3 years ago
9

Convert -90.0°F to -5.0°c to kelvin

Physics
1 answer:
Ratling [72]3 years ago
4 0

-90.0 °F  =  -67 and 7/9 °C

-90.0 °F also = +205.372 K

-5.0 °C  =  +23 °F

-5.0 °C also  =  +268.15 K

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3 years ago
Consider a long cylindrical charge distribution of radius R with a uniform charge density rho. Find the electric field at distan
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Answer: Ok, first lest see out problem.

It says it's a Long cylindrical charge distribution, So you can ignore the border effects on the ends of the cylinder.

Also by the gauss law we know that E¨*2*pi*r*L = Q/ε0

where Q is the total charge inside our gaussian surface, that will be a cylinder of radius r and heaight L.

So Q= rho*volume= pi*r*r*L*rho

so replacing : E = (1/2)*r*rho/ε0

you may ask, ¿why dont use R on the solution?

since you are calculating the field inside the cylinder, and the charge density is uniform inside of it, you don't see the charge that is outside, and in your calculation actuali doesn't matter how much charge is outside your gaussian surface, so R does not have an effect on the calculation.

R would matter if in the problem they give you the total charge of the cylinder, so when you only have the charge of a smaller r radius cylinder, you will have a relation between r and R that describes how much charge density you are enclosing.

3 0
3 years ago
A 50-cm wire placed in an east-west direction is moved horizontally to the north with a speed of 2.0 m/s. the horizontal compone
Strike441 [17]

When a wire is moved inside uniform magnetic field then its free electrons will experience magnetic force on it due to which wire will have potential difference at its ends.

Now here we will have magnetic field due to earth and wire is moving in this constant field so induced emf is given by formula

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given that

B = 25\mu Tj - 50\mu Tk

v = 2 m/s j

L = 0.50 m (-i)

now by using the above formula we will have

EMF = 2(j) .(25\mu j - 50\mu k) x (-0.50 i)

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5 0
3 years ago
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Based on your problem where as ask for the distance of the ball drop between the pitchers mound and the home plate and with a given of the speed of ball is 43m/s and the homeplates is 60.6ft away. Based on my step by step procedure and also considering the value of gravity by 9.8m/s^2 i came up with the distance of 144m away
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3 years ago
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An extreme skier, starting from rest, coasts down a mountain slope that makes an angle of 25.0 with the horizontal. The coeffici
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Answer:

V = 10.88 m/s

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using the equation

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let the speed just before she lands be "V"

using conservation of energy

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V = 10.88 m/s

6 0
3 years ago
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