Answer:
<em>Choice: c. 6sec</em>
Explanation:
<u>Horizontal Launch
</u>
When an object is thrown horizontally with a speed (v) from a height (h), it describes a curved path ruled by gravity until it finally hits the ground.
The horizontal component of the velocity is always constant because no acceleration exists in that direction, thus:
The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:
Where 
To calculate the time the object takes to hit the ground, we use the same formula as for free-fall, since the time does not depend on the initial speed:
The marble rolls the edge of the table at a height of h=180 m, thus:
t = 6 sec
Choice: c. 6sec
Well, Velocity is the speed of something in a given direction, and speed is the rate at which someone or something is able to more or operate. They both invlove speed, so this is a hard one, but I wold say either B or D
Answer:
A) Φ = 0
, B) T = 7.76 s
Explanation:
A) to find the value of the phase constant replace the value
0 = a sin (b (0- 0) + Φ)
0 = sin Φ
Φ = sin⁻¹ 0
Φ = 0
B) the period is defined by time or when the movement begins to repeat itself
So that the sine function is repeated when the angle passes 2pi
b (x- ct) = 2pi
If we are at a fixed point x = 0
b c t = 2pi
t = 2π / bc
Let's calculate
T = 2π / (33.05 245)
T = 7.76 s
The X-axis of the H-R Diagram indicates the star's surface temperature in degrees Kelvin. The Y-axis, on the other hand, indicates luminosity, or brightness.
Main sequence refers to a roughly diagonal, slightly S-curved line stretching between the upper-left and lower-right corners on which main sequence stars chart. They maintain a predictable relationship between luminosity and temperature: the brighter, the hotter. The upper-right quadrant of the H-R diagram is home to newly discovered red giants while the lower-left quadrant of the H-R Diagram belongs almost exclusively to white dwarfs.
<span>By algebra, d = [(v_f^2) - (v_i^2)]/2a.
Thus, d = [(0^2)-(15^2)]/(2*-7)
d = [0-(225)]/(-14)
d = 225/14
d = 16.0714 m
With 2 significant figures in the problem, the car travels 16 meters during deceleration.</span>
