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3 years ago

Pro-Cut Rotor Matching Systems provide a non-directional finish without performing additional swirl sanding — true or false?

Engineering

1 answer:

KATRIN_1 [288]3 years ago

8 0

Answer:True

Explanation:Rotor matching is a term used to describe the process through a brake rotor is aligned to the hub and bearing assembly to produce a smooth, flat, and straight friction surface.

Rotor matching is an essential process which is required to prevent swirling of a break when a vehicle is stopping, rotor matching is needed for efficient and effective break system performance as it is one of the main determinant factors for accidents arising from break failures.

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Ayden read 84 pages in 2 hours. At that rate, how many pages can he read in 5 hours

Papessa [141]

Answer:210

Explanation:

Divide 84 by 2 and then multiply by 5 by that number

3 0

4 years ago

Read 2 more answers

Parity Detect of Three Inputs 20 pts. (EVEN) a) Draw a function table showing the three data lines and the output function F. 4

DIA [1.3K]

Answer:

See attached picture.

Explanation:

4 0

3 years ago

Technician A says that you don’t need to use an exhaust extraction system when working on vehicles equipped with a catalytic con

pav-90 [236]

Answer:

Technician B

Explanation:

When working on vehicles which are equipped with a catalytic coverter, the best practice of asphyxiating someone is to use carbon monoxide. This implies that you need an extraction sytem. Therefore, technician A is wrong by assuming no need of the system. In conclusion, technician B is correct.

8 0

3 years ago

2- A 2-m3 insulated tank containing ammonia at -20 C, 80% quality, is connected by a valve to a line flowing ammonia at 2 MPa, 6

alekssr [168]

Answer:

The valve should be closed at 1081 kPa ⇒ 11 bar

Explanation:

$Q_{C_V} + m_ih_i = m_2u_2 - m_1u_1 + W_{C_V}$

$Q_{C_V} = W_{C_V} = 0$

$m_1 = \frac{V}{v_1} = \frac{2}{0.49927} = 4.006 kg$

$m_i = m_2 - m_1 = 15 - 4.006 = 10.994 kg$

$u_1 = 1057.5, h_i = 1509.9$

$u_2 = m_ih_i + m_1u_1$

$m_2 = \frac{[10.994*1509.9] + [4.006*1057.5]}{15} = 1389.1 kJ/kg$

$v_2 = \frac{V}{m_2} = \frac{2}{15} = 0.1333 m^3/kg$

Therefore, v₂, u₂ fix state 2.

By trial and error, P₂ = 1081 kPa & T₂ = 50.4° C

1081 kPa ⇒ 11 bar

8 0

4 years ago

A mechanical system comprises three subsystems in series with reliabilities of 98, 96, and 94 percent. What is the overall relia

Westkost [7]

Answer:

<h2> The overall reliability of the system is 88%</h2>

Explanation:

When solving for the reliability of a complex machine, that is a machine that has more than one component, the reliability of the machine is the products of all individual components.

Given the

reliabilities of 98%,

96%, and

94%

Converting to decimals we have

98/100= 0.98

96/100= 0.96

94/100= 0.94

The product of all reliability is

0.98* 0.96 0.94= 0.88

now converting back to percent we have

0.88*100= 88%

3 0

4 years ago