Answer:
The moles present in 60 g of calcium are 1.5 moles.
The amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.
<h3>What is the amount of heat required to melt an iceberg that has a volume of about 3.1 x 1013 m³?</h3>
The heat required to melt a unit mass of ice is known as the latent heat of fusion.
The latent heat of fusion of ice of 1 kg= 334 kJ of heat
Mass of iceberg = 3.1 x 10¹³ m³ * 917 kg = 2.8427 * 10¹⁶ kg
Amount of heat required = 2.8427 * 10¹⁶ * 334 = 9.58 * 10¹⁸ kJ.
Therefore, the amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.
Learn more about latent heat of fusion at: brainly.com/question/87248
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Answer:
b. John has to pour each liquid into a container with the same mass and then compare them
would be the correct answer. Hope this helps!
Explanation:
The number of moles is simply calculated by taking the ratio of mass over the molar mass. The molar mass of silver nitrate AgNO3 is 169.87 g/mol. Therefore:
number of moles AgNO3 = 100 g / (169.87 g/mol)
number of moles AgNO3 = 0.59 moles
C=2.41 g/L
m(NaCl)=0.291 g
c=m(NaCl)/v
v=m(NaCl)/c
v=0.291/2.41= 0.1207 L = 120.7 mL
