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swat32
3 years ago
10

Which of the following statements is true?

Chemistry
2 answers:
VikaD [51]3 years ago
7 0

The answer is likely to be A

Zarrin [17]3 years ago
5 0

Answer: The awnser us B

Explanation: Because both of the temperatures for condensing and freezing are the same thing 32 degrees.

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2. State one difference between gas and vapour. Which of the following substance in the gaseous state should be called a vapour?
Neporo4naja [7]
Difference between Gas and Vapour:
                                                          
Gas:
        A thermodynamic state in which a substance exists only in one phase i.e. Gas phase. In above given examples N₂, He and CO₂ exists as gases at room temperature. These gases cannot form a solid or liquid phase along with gas phase as these states requires very low temperatures.

Vapours:
               It is a thermodyanamic state in which a substance exists in more than one phase. In given options Sulfur can exist in vapor state. This is because sulfur exists in a cyclic or chain form due to catenation (self linkage property). Therefore, a lower members of S allotrops can form a vapours.
3 0
3 years ago
What refers to the attractive forces that exist between molecules?​
CaHeK987 [17]
Intermolecular forces are the forces of attraction or repulsion which act between neighboring particles (atoms, molecules, or ions ). These forces are weak compared to the intramolecular forces, such as the covalent or ionic bonds between atoms in a molecule.
8 0
2 years ago
A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilomete
lys-0071 [83]

ke prop to v^2


ke1/v1^2=ke2/v2^2


400/50x50=joules/100x100


400x2x2


1600j

8 0
3 years ago
Given the chemical equation: 2 Pb + O2 → 2 PbO, if 51.8 grams of Pb are formed in this reaction, then 8.00 grams of O2 must have
Nutka1998 [239]

Answer:

If 51.8 of Pb is reacting, it will require 4.00 g of O2

If 51.8 g of PbO is formed, it will require 3.47 g of O2.

Explanation:

Equation of the reaction:

2 Pb + O2 → 2 PbO

From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO

Molar mass of Pb = 207 g

Molar mass of O2 = 32 g

Molar mass of PbO = 207 + 32 = 239 g

Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO

= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO

Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.

If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2

7 0
3 years ago
Which of the following is true about an atom of silver
kati45 [8]

Answer:

where is options.

tell me

4 0
3 years ago
Read 2 more answers
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