Ba(NO₃)₂ + Na₂SO₄ → BaSO₄ + NaNO₃
By Trial and error.
Ba(NO₃)₂ + Na₂SO₄ → BaSO₄ + 2NaNO₃
Check:
LHS RHS
Ba 1 1
N 2 2
S 1 1
O 3*2 + 4 = 10 4 + 2*3 = 10
Either the first one or the second one but i believe it’s the stricter on
At a temperature of 298 K, the Henry's law constant is 0.00130 M/atm for oxygen. The solubility of oxygen in water 1.00 atm would be calculated as follows:
<span>S = (H) (Pgas) = 0.00130 M / atm x 0.21 atm = 0.000273 M
</span>
At 0.890 atm,
<span>S = (H)(Pgas) = 0.00130 M / atm x 0.1869 atm = 0.00024297 M</span>
<span>
If atmospheric pressure would suddenly change from 1.00 atm to 0.890 atm at the same temperature, the amount of oxygen that will be released from 3.30 L of water in an unsealed container would be as follows</span>
<span>
3.30 L x (0.000273 mol / L) = 0.0012012 mol</span>
3.30 L x (0.00024297 mol / L) = 0.001069068 mol
0.0012012 mol - 0.001069068 mol = 0.000132 mol
Answer: no
Explanation: we need a picture