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2 years ago

Which force is represented by the arrow at

Physics

2 answers:

shutvik [7]2 years ago

7 0

A is pulling the block straight down toward the center of the Earth, no matter what the slope of the plane may be. A is the force of gravity.

The directions of B and C both depend on the slope of the plane.

B is a force that's parallel to the plane, pulling the block UP the plane. B is the force of friction.

C is a force perpendicular to the plane, preventing the block from falling down through the plane. C is the normal force.

PilotLPTM [1.2K]2 years ago

7 0

Answer:

A is pulling the block straight down toward the center of the Earth, no matter what the slope of the plane may be. A is the force of gravity.

The directions of B and C both depend on the slope of the plane.

B is a force that's parallel to the plane, pulling the block UP the plane. B is the force of friction.

C is a force perpendicular to the plane, preventing the block from falling down through the plane. C is the normal force.

Explanation:

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A circular loop of wire with a diameter of 0.626 m is rotated in a uniform electric field to a position where the electric flux

Mila [183]

Answer:

C) 2.44 × 106 N/C

Explanation:

The electric flux through a circular loop of wire is given by

$\Phi = EA cos \theta$

where

E is the electric field

A is the cross-sectional area

$\theta$ is the angle between the direction of the electric field and the normal to A

The flux is maximum when $\theta=0^{\circ}$ , so we are in this situation and therefore $cos \theta =1$ , so we can write

$\Phi = EA$

Here we have:

$\Phi = 7.50\cdot 10^5 N/m^2 C$ is the flux

d = 0.626 m is the diameter of the coil, so the radius is

r = 0.313 m

and so the area is

$A=\pi r^2 = \pi (0.313 m)^2=0.308 m^2$

And so, we can find the magnitude of the electric field:

$E=\frac{\Phi}{A}=\frac{7.50\cdot 10^5 Nm^2/C}{0.308 m^2}=2.44\cdot 10^6 N/C$

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3 years ago

The gases cast off by a dying star are called

lozanna [386]

Planetary Nebulae hope that helps

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3 years ago

Read 2 more answers

A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resist

7nadin3 [17]

Explanation:

The power P dissipated by a heater is defined as

$P = VI$

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

$I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}$

b) The resistance <em>R</em><em> </em>of the heater is

$P = VI = (IR)I = I^2R$

where $V= IR$ is our familiar Ohm's Law.

$\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}$

$R = 110.8\:Ω$

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3 years ago

A disk with a hole has inner radius rin and outer radius rout. the disk is uniformly charged with total charge q. find an expres

Effectus [21]

Here it is. I used the surface charge density σ as q/Area, and then wrote it out in terms of q at the end

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3 years ago

1. Identify the significance of the following terms to the subject of the Civil War.

DanielleElmas [232]

What following terms I don’t see any please make your question clear

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3 years ago