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3 years ago

Select the two statements that are true about the equation y - 5= 12(x – 4).

Mathematics

1 answer:

AnnZ [28]3 years ago

6 0

Answer:

fssrtddfxxsrtdtdyukvvvdsthcg nnjnhdddyuj

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What’s the sum of 4/10 + 32/100

Serggg [28]

The answer is 0.72. Hope I helped!!

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3 years ago

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Fiona is gathering signatures on a petition to save the Orangutans. If she gets 4 times the number of signatures that she has ri

mixer [17]

The equation would be 4n=8000
to solve, divide 8000/4=2000, she has collected 2,000 signatures so far

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3 years ago

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You are standing on a small fire tower 50 feet from a tree. You notice a squirrel in the tree. You measure the angle of depressi

irina [24]

Answer:

44.81 feet

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the right triangle ACD

Find the length side AC (height of the small fire tower)

$tan(52^o)=\frac{AC}{50}$ ---> by TOA (opposite side divided by the adjacent side)

Solve for AC

$AC=tan(52^o){50}$

$AC=64\ ft$

step 2

In the right triangle ABE

Find the length side AB

$tan(21^o)=\frac{AB}{50}$ ---> by TOA (opposite side divided by the adjacent side)

solve for AB

$AB=tan(21^o){50}$

$AB=19.19\ ft$

step 3

How many feet off the ground is the squirrel?

Subtract the length side segment AB from the length side segment AC

$64-19.19=44.81\ ft$

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3 years ago

Amir says the graph of<br> y= x2 + 16 has -4 as a zero. Is Amir correct?<br> Explain.

sukhopar [10]

Answer:

Amir is wrong

Step-by-step explanation:

The function y = x² + 16 is positive for any value of x, hence the graph has no intersection with the x-axis and therefore has no real zero's.

If no zero's, -4 also can't be its zero.

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2 years ago

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Sofia hits a softball straight up. the equation h= -16t^2 + 90t models the height h, in feet, of the ball after t seconds. How l

andrezito [222]

It is in the air 5.625 seconds.

Using the quadratic formula,

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}
\\
\\=\frac{-90\pm \sqrt{90^2-4(-16)(0)}}{2(-16)}
\\
\\=\frac{-90\pm \sqrt{8100-0}}{-32}
\\
\\=\frac{-90\pm \sqrt{8100}}{-32}=\frac{-90\pm90}{-32}
\\
\\=\frac{-90+90}{-32}\text{ or }\frac{-90-90}{-32}=\frac{0}{32}\text{ or }\frac{-180}{-32}
\\
\\=0\text{ or }5.625$

0 is when the ball is first launched, 5.625 is when it hits the ground again.

4 0

3 years ago