Question

What is the molecular shape of BF3?

Answer 1

Answer: molecular shape of $BF_3$ is trigonal planar.

Explanation: Formula used

$:{\text{Number of electrons}} =\frac{1}{2}[V+N-C+A]$

where, V = number of valence electrons present in central atom i.e. boron = 3

N = number of monovalent atoms bonded to central atom=3

C = charge of cation = 0

A = charge of anion = 0

$BF_3:$

${\text{Number of electrons}} =\frac{1}{2}[3+3-0+0]=3$

The number of electrons is 3 that means the hybridization will be $sp^2$ and the electronic geometry of the molecule will be trigonal planar.

Answer 2

Trigonal planar. Hope that helps!