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d1i1m1o1n [39]
3 years ago
10

Which describes the letter that belongs where the question mark is?

Chemistry
2 answers:
Evgesh-ka [11]3 years ago
4 0

Explanation:

Are you referring to a variable?

Fofino [41]3 years ago
3 0
Dbdndnnddnbdbdbbdbnddnjssnsbsnksnd
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What is the main exception in the atomic radius? Explain.
yarga [219]

Answer:

The atomic radius of atoms generally decreases from left to right across a period. There are some small exceptions, such as the oxygen radius being slightly greater than the nitrogen radius. Within a period, protons are added to the nucleus as electrons are being added to the same principal energy level.

hope this helps!

7 0
2 years ago
27. The density of nickel is 8.91 g/cm3. How large a cube, in cm3, would contain 2.00 x 10^24 atoms of nickel? Use dimensional a
jok3333 [9.3K]

Answer : The volume of the cube is, 21.88cm^3

Solution : Given,

Density of nickel = 8.91g/cm^3

Number of nickel atoms = 2\times 10^{24}

Molar mass of nickel = 58.7 g/mole

First we have to calculate the moles of nickel.

As, 6.022\times 10^{23} atoms form 1 mole of nickel

So, 2\times 10^{24} atoms form \frac{2\times 10^{24}}{6.022\times 10^{23}}=3.321 moles of nickel

The moles of nickel = 3.321 moles

Now we have to calculate the mass of nickel.

\text{ Mass of Ni}=\text{ Moles of Ni}\times \text{ Molar mass of Ni}

\text{ Mass of Ni}=(3.321moles)\times (58.7g/mole)=194.94g

The mass of nickel = 194.94 g

Now we have to calculate the volume of nickel.

Density=\frac{Mass}{Volume}

8.91g/cm^3=\frac{194.94g}{Volume}

Volume=21.88cm^3

Therefore, the volume of the cube is, 21.88cm^3

4 0
3 years ago
Which sentence best describes an igneous intrusion
Ulleksa [173]
What are the sentences? 
It would help to see the sentences.
5 0
3 years ago
Read 2 more answers
A gas held at constant volume is heated from -5 degrees C to 50 degrees C, if the initial pressure is 1.0 atm, what is the new p
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1.21 atm, assuming the gas behaves ideally
8 0
2 years ago
How do I do this and what are the answers?
vodka [1.7K]
I cannot see your question to help you... sorry
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3 years ago
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