Answer:
2) f = 0.707 Hz
Explanation:
Given m₁ = 1.0 kg , f₁ = 1.0 Hz
So using the equation
f₁ = ( 1 / 2 π ) * √K / m₁
Solve to determine K' constant of spring
K = m * ( 4 π ² * f ² )
K = 1.0 kg * ( 4 π ² 1.0² Hz )
K = 39.4784176
So given 2.0 kg the frequency can be find using formula
f₂ = ( 1 / 2 π ) * √K / m₂
f₂ = ( 1 / 2 π ) * √39.4784176 / 2.0 kg
f₂ = 0.707 Hz
Answer:
E. Some charges in the region are positive, and some are negative.
Explanation:
Electric potential is given as;

where;
W is the work done in moving a charge between two points which have a difference in potential
Q is quantity of charge in the given region
If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.
Therefore, the correct statement in the given options is "E"
E. Some charges in the region are positive, and some are negative.
Answer:
w = 706.32 [N]
Explanation:
The force due to gravitational acceleration can be calculated by means of the product of mass by gravitational acceleration.
w = m*g
where:
w = weight [N] (units of Newtons)
m = mass = 72 [kg]
g = gravity acceleration = 9.81 [m/s²]
Then we have:
![w = 72*9.81\\w = 706.32 [N]](https://tex.z-dn.net/?f=w%20%3D%2072%2A9.81%5C%5Cw%20%3D%20706.32%20%5BN%5D)