The mass defect and energy released is associated in the formula expressed below:
E = delta m * c2 where c is the speed of light equal to 3x 10 ^8 m/s. Substituting, E equal to 9.20 x 1011 KJ, delta m is equivalent to 0.0102 kg. The answer hence is A.
Explanation:
Newton's first law of motion
state If a body is at rest it remain at reast and if it is in a motion it continue it's motion unless a net external force acting on it.
This law also called law of inertia
Newton's second law motion
states that acceleration to the force acting on the body and inversely proportional to the mass of the body
Newton's third law motion It is not to exert a force abody without the body exerting a forces in the opposite direction
These forces are called action and reaction force.
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When the object is lifted 6 meters of the ground , then lifted to 12 meters, it is lifted twice as high ( 6 x 2 = 12).
This means the potential energy is also doubled.
The dummy is moving with a speed 0 km/h relative to the seat in which it is sitting.
If the relative speed was non-zero, the dummy would move away from its seat, which contradicts the problem formulation.
Torque acting dowward = 6 x 0.5 = 3 Nm
Torque acting to the right = 5 x 1 = 5 Nm
5 - 3 = 2 Nm
inertia = 1/2 mr^2
0.5 x 10 x 1^2 = 5 kg-m^2
2/5 = alpha = 0.4 rad /s^2
Hope this helps