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ankoles [38]
2 years ago
7

Draw a winding path that covers a distance of 70 miles and finishes with a displacement 20 miles soulthwest of the starting poin

t. Label your diagram with the distance and direction traveled.
Physics
1 answer:
EleoNora [17]2 years ago
7 0

Distance is indeed a scalar amount that also refers to "<em><u>how the ground an object has encased</u></em>", and the Displacement is a vector thing that leads "<em><u>to the extent to which an object is located</u></em>", and the further calculation can be defined as follows:

Given:

distance= 70 miles

displacement = 20 miles

  • Displacement formula: \bold{Velocity = \frac{displacement}{time}}
  • Distance formula: \bold{Distance = speed \times time}

Please find the graph in the attached file.

Learn more:

brainly.com/question/9290794

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If the slope of a line on a speed-time graph is 0 and it is not on the x-axis, what is the object doing?
Zinaida [17]
It is moving at a constant speed, not accelerating.
4 0
3 years ago
camera was able to deliver 1.3 frames per second for this photo, and that the car has a length of approximately 5.3 meters. Usin
son4ous [18]

The question is incomplete. Here is the complete question.

The image below was taken with a camera that can shoot anywhere between one and two frames per second. A continuous series of photos was combined  for this image, so the cars you see are in fact the same car, but photographed at differene times.

Let's assume that the camera was able to deliver 1.3 frames per second for this photo, and that the car has a length of approximately 5.3 meters. Using this information and the photo itself, approximately how fast did the car drive?

Answer: v = 6.5 m/s

Explanation: The question asks for velocity of the car. Velocity is given by:

v=\frac{\Delta x}{\Delta t}

The camera took 7 pictures of the car and knowing its length is 5.3, the car's displacement was:

Δx = 7(5.3)

Δx = 37.1 m

The camera delivers 1.3 frames per second and it was taken 7 photos, so time the car drove was:

1.3 frames = 1 s

7 frames = Δt

Δt = 5.4 s

Then, the car was driving:

v=\frac{37.1}{5.4}

v = 6.87 m/s

The car drove at, approximately, a velocity of 6.87 m/s

7 0
3 years ago
What is the physical representation of the area under a force versus extension or compression curve?
lidiya [134]

The compression curve would be theoretically given for a system of bodies in which the spring applies the force (Although in the same way the following process can be extrapolated to any system, depending on the type of Force to consider) For a spring mass system, the strength is given by Hooke's law as

F = Kx

Where,

K  = Spring constant

x = Displacement

If we integrate based on distance we would have

\int F = \int K x dx

This integral represents the area under the Force Curve based on each distance segment traveled.

\int F = K \int xdx

\int F = K (\frac{1}{2} x^2)

\int F = \frac{1}{2} Kx^2

This is the same formula that represents the elastic potential energy of a body. Therefore the correct answer is D.

5 0
3 years ago
In a hydroelectric dam the potential energy of lake water is transformed into _ energy as it begins to more.
Marianna [84]

Answer:

mechanical energy

Explanation:

7 0
2 years ago
Read 2 more answers
II) A 0.40-kg ball, attached to the end of a horizontal ord, is rotated in a circle of radius 1.3 m on a friction- less horizont
Lostsunrise [7]

Hi there!

In this instance, the object spinning in a horizontal circle will experience a net force in the horizontal direction due to tension.

The net force is equivalent to the centripetal force, so:

∑F = T

mv²/r = T

Solve for v:

v = √rT/m

v = 13.96 m/s

3 0
2 years ago
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