Answer:
Heat losses by convection, Qconv = 90W
Heat losses by radiation, Qrad = 5.814W
Explanation:
Heat transfer is defined as the transfer of heat from the heat surface to the object that needs to be heated. There are three types which are:
1. Radiation
2. Conduction
3. Convection
Convection is defined as the transfer of heat through the actual movement of the molecules.
Qconv = hA(Temp.final - Temp.surr)
Where h = 6.4KW/m2K
A, area of a square = L2
= (0.25)2
= 0.0625m2
Temp.final = 250°C
Temp.surr = 25°C
Q = 64 * 0.0625 * (250 - 25)
= 90W
Radiation is a heat transfer method that does not rely upon the contact between the initial heat source and the object to be heated, it can be called thermal radiation.
Qrad = E*S*(Temp.final4 - Temp.surr4)
Where E = emissivity of the surface
S = boltzmann constant
= 5.6703 x 10-8 W/m2K4
Qrad = 5.6703 x 10-8 * 0.42 * 0.0625 * ((250)4 - (25)4)
= 5.814 W
if a pilot-operated check valve (POC) does not check flow, you will see The symptoms and symptoms of a failing swing test valve are regularly audible.
<h3>
What happens when the pilot valve reaches set strain?</h3>
When the pilot valve reaches set strain it opens and releases the strain from the dome. The piston is then unfastened to open and the principle valve exhausts the machine fluid. The manage pilot opens both to the principle valve exhaust pipe or to the atmosphere.
Pilot operated test valves paintings through permitting unfastened go with the drift from the inlet port thru the opening port. Supplying a pilot strain to the pilot port permits go with the drift withinside the contrary direction. Air strain on the pinnacle of the poppet meeting opens the seal permitting air to go with the drift freely.
Read more about the pilot valve :
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Answer:
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Explanation:
A length of pipe will weigh the most when O A. part dimensions are such that the pipe is in the MMC. O B. the OD and ID are at the minimum allowable limit. OC. the OD and ID are at the maximum allowable limit. OD.part dimensions are such that the pipe is in the LMC
Answer:
Work transfer is - 97.02 KJ. It means that work is given to the system.
Heat transfer = - 97.02 KJ . It means that heat is rejected from the system.
Explanation:
Given that
m= 3 kg
P₁=2 bar
T=T₁=T₂=30 °C
T=303 K
P₂=2.5 bar
PV= Constant
This is the isothermal process .
We know that work for isothermal process given as
For air
R= 0.287 KJ/Kg.K
Now by putting the values
W= - 97.02 KJ
So the work transfer is - 97.02 KJ. It means that work is given to the system.
We know that for ideal gas internal energy is the only function of temperature.The change in internal energy ΔU
ΔU = m Cv ΔT
Here ΔT= 0
So
ΔU =0
From first law of thermodynamics
Q= ΔU +W
ΔU = 0
Q= W
Q= - 97.02 KJ
Heat transfer = - 97.02 KJ . It means that heat is rejected from the system.
