Answer:
(a) 0.255 rad/s.
(b) 149.02 m
Explanation:
(a)
The expression for the average angular speed of the car is given as,
ω = 2π/T........................... Equation 1
Where ω = Angular speed, T = period of the car, π = pie.
Given: T = 24.6 s,
Constant: π = 3.14
Substitute into equation 1
ω = 2(3.14)/24.6
ω = 0.255 rad/s.
(b)
The expression for tangential speed, angular speed and radius s given as
s = rω................... equation 2
Where s = tangential speed, r = radius of the track, ω = angular speed.
make r the subject of the equation
r = s/ω................ Equation 3
Given: s = 38 m/s, ω = 0.255 rad/s
Substitute into equation 3
r = 38/0.255
r = 149.02 m.
Hence the radius of the track = 149.02 m
