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3 years ago

Which change can make a generator stronger?

Physics

2 answers:

il63 [147K]3 years ago

9 0

the answer is D on Edge

Mice21 [21]3 years ago

4 0

<span>increasing the number of coils in the armature
</span>

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What is the potential energy at point e when the total mechanical energy is 4900 for the 100 kg moving at 2 m/ s

Leto [7]

Answer:

B. 4700 J

Explanation:

Given the following data;

Mechanical energy = 4900J

Mass = 100kg

Velocity = 2m/s

To find the potential energy;

Mechanical energy = kinetic energy + potential energy

First of all, we would determine the kinetic energy of the object;

K.E = ½mv²

K.E = ½*100*2²

K.E = 50*4

K.E = 200 J

Substituting into the equation, we have;

4900 = 200 + P.E

P.E = 4900 - 200

P.E = 4700 Joules

4 0

3 years ago

If the coefficient of static friction between your coffee cup and the horizontal dashboard of your car is µs = 0.800, how fast c

Cloud [144]

Answer:

Before start of slide velocity will be 14.81 m/sec

Explanation:

We have given coefficient of static friction $\mu =0.8$

Angle of inclination is equal to $\Theta =tan^{-1}\mu$

$\Theta =tan^{-1}0.8=38.65^{\circ}$

$tan{38.65^{\circ}}=0.8$

Radius is given r = 28 m

Acceleration due to gravity $g=9.8m/sec^2$

We know that $tan\Theta =\frac{v^2}{rg}$

$0.8=\frac{v^2}{28\times 9.8}$

$v^2=219.52$

$v=14.816m/sec$

So before start of slide velocity will be 14.81 m/sec

3 0

3 years ago

A __________ provides a visual summary of the improvements that a data mining project provides on a binary classification proble

babymother [125]

Answer:

Option (B)

Explanation:

A lift chart usually refers to a graphical representation that is mainly used in order to improve the drawbacks of a mining model by making a comparison with any random guess, and also helps in determining the changes that occur in terms of lift scores.

It describes the binary classification of the problems associated with the mining activity. This type of chart is commonly used to differentiate the lift scores for a variety of models, and picking the best one out of all.

Thus, the correct answer is option (B).

5 0

4 years ago

What area must the plates of a capacitor be if they have a charge of 5.7uC and an electric field of 3.1 kV/mm between them? O 0.

kirill [66]

Answer:

Area of the plates of a capacitor, A = 0.208 m²

Explanation:

It is given that,

Charge on the parallel plate capacitor, $q = 5.7\ \mu C=5.7\times 10^{-6}\ C$