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Sergeu [11.5K]
2 years ago
5

Which change can make a generator stronger?

Physics
2 answers:
il63 [147K]2 years ago
9 0

the answer is D on Edge

Mice21 [21]2 years ago
4 0
<span>increasing the number of coils in the armature
</span>

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As the temperature of an object rises, so does the
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C. The object is not in motion, ruling out A. We are not adding mass in any way, nor does adding heat to object increase its mass, therefore also ruling out B. Finally, we are not changing the object's position in such a way that gives it a higher ability to do work, ruling out D. 
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What is the magnification of a real image if the image is 15.0 cm from a lens and the object is 60.0 cm from the lens?
Hoochie [10]

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soluble

Explanation:

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How much work is done on an object that is moved to acquire a displacement of 5 meters when 500 Newtons of force was exerted?​
grandymaker [24]

Answer:

2,500 Joules (J) or Newton Meter (N M)

Explanation:

Work = Force x Distance

The force in this equation is 500 Newtons. The distance (displacement) is 5 meters. Plug it into the equation above.

Work = 5m x 500n

Work = 2,500 Joules or Newton-Meters.

Therefore 2,500 Joules or Newton Meters of work is done on an object.

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2 years ago
When would the carrying capacity of an area be most likely to change? Choose the correct answer.
pickupchik [31]

Answer:

when resources remain the same

Explanation:

The capacity of an area will change if the available resources remain the same, especially if the population is changing.

8 0
3 years ago
A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diame
dalvyx [7]

Complete question:

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diameter 1.0 m. The ball makes 2.0 revolutions every 1.0 s. What are the magnitude and direction of the acceleration of the ball?

Answer:

The acceleration of the ball is 78.98 m/s², directed inwards

Explanation:

Given;

mass of the ball, m = 175 g

radius of the circle, r = 0.5 m

angular speed of the ball, ω = 2 rev/s

The magnitude of the centripetal acceleration of the ball is calculated as follows;

a_c = \omega^2 r\\\\where;\\\omega \ is \ angular \ speed \ in \ rad/s\\\\a_c = (2\ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} )^2 \times (0.5 \ m)\\\\a_c =78.98 \ m/s^2

The centripetal acceleration is directed inwards.

8 0
2 years ago
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