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3 years ago

Calculate the molar solubility of lead thiocyanate in 1.00 M KSCN.

1 answer:

7 0

You have to make an assumption or estimation here: (don't think about the 1.00 M KSCN)
Since 1.00M KSCN provides a common ion source of SCN-. Therefore, you will have a <span>1.00 M SCN-.
</span><span>[Pb+2][SCN-] ~ 0.01 x 0.02^2 = 4E-6
</span> Pb(SCN)2 <---> Pb++ + 2SCN- <span>

</span>Bringing 1.00M SCN- back in the problem. 1.00M + 0.02M, ignoring the SCN-, and calculating the <span> [Pb+2]:
</span><span>
</span><span>Ksp = [Pb++][SCN-]^2
</span>2.00E-5 = [Pb++](1.00)^2

<span>[Pb++] = 2.00E-5 M </span>

<span>The mass balance shows that: </span>

<span>[Pb++] = [Pb(SCN)2] </span>

So [Pb(SCN)2] = 2.00E-5 M in 1.00 M KSCN.

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The drug labetalol has a dose of 300 mg and is administered in 300 mL of an intravenous infusion at a rate of 2 mg/min. Using an

Evgesh-ka [11]

Answer:

Explanation:

From the given information:

Since 300 ml of intravenous infusion contains 300 mg of drugs;

Then; 1 ml of intravenous infusion contains (x) amount of drugs

(x) amount of drugs = (300 mg × 1 ml)/ 300 ml

(x) amount of drugs = 1 mg.ml

To calculate the drip rate in drops/minutes by applying conversion factors.

$rate (\dfrac{ in \ drops }{minute })= \dfrac{2 \ mg }{min } \times \dfrac{20 \ drops}{1 \ ml} \times \dfrac{1 \ ml }{1 \ mg }$

$rate (\dfrac{ in \ drops }{minute }) = 40 \ drops / min$

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3 years ago

a 1.513 g sample of khp (c8h5o4k) is dissolved in 50.0 ml of di water. when the khp solution was titrated with naoh, 14.8 ml was

JulijaS [17]

molar mass of KHP ( C8H5O4K)= 8*12+5+4*16+39=204

( atomic weights : C=12, H=1, K=39 and O= 16)

moles of KHP= mass/molar mass = 1.513/204 =0.0074

The reaction between KHP and NaOH is

KHC8H4O4(aq) + NaOH(aq) => KNaC8H4O4(aq) + H2O(l)

1 mole of KHP requires 1 mole of NaOH;

moles of KHP=0.0074

moles of NaOH= 0.0074

concentration of NaOH= moles/ Volume in L, 1000ml= 1L, 14.8ml= 14.8/1000L=0.0148L

concentration of NaOH=0.0074/0.0148=0.5M

The molarity of NaOH is 0.5M

Molar Mass:

In chemistry, the molar mass of a compound is defined as the mass of a sample of that compound divided by the amount of substance. This is the number of moles of that sample measured in moles.

Molarity:

Molarity is used to describe the concentration of a solution. Molarity, also called molarity, is the number of moles of solute (dissolved substance) per liter of solution.

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11 months ago

Write the formula of the conjugate acid of HCO₂⁻.

Alex

Taking into account the Brønsted-Lowry acid-base theory, the conjugate acid of HCO₂⁻ is H₂CO₂.

<h3>Brønsted-Lowry acid-base </h3>

The Brønsted-Lowry acid-base theory (or the Brønsted-Lowry theory) identifies acids and bases based on whether the species accepts or donates protons or H⁺.

According to this theory, acids are proton donors while bases are proton acceptors. That is, an acid is a species that donates an H⁺ proton while a base is a chemical species that accepts an H⁺ proton from the acid.

So, reactions between acids and bases are H⁺ proton transfer reactions.

<h3>Conjugate base and conjugate acid</h3>

Then, a conjugate base is an ion or molecule resulting from the acid that loses the proton, while a conjugate acid is an ion or molecule resulting from the base that gains the proton:

acid + base ⇄ conjugate base + conjugate acid

<h3>Conjugate acid of HCO₂⁻</h3>

Like a conjugate acid is an ion or molecule resulting from the base that gains the proton, the conjugate acid of HCO₂⁻ is H₂CO₂.

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2 years ago

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