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vovikov84 [41]
3 years ago
5

Calculate the molar solubility of lead thiocyanate in 1.00 M KSCN.

Chemistry
1 answer:
Rzqust [24]3 years ago
7 0
You have to make an assumption or estimation here: (don't think about the 1.00 M KSCN)
Since 1.00M KSCN provides a common ion source of SCN-. Therefore, you will have a <span>1.00 M SCN-.
</span><span>[Pb+2][SCN-] ~ 0.01 x 0.02^2 = 4E-6 
</span> Pb(SCN)2 <---> Pb++ + 2SCN- <span>

</span>Bringing 1.00M SCN- back in the problem. 1.00M + 0.02M, ignoring the SCN-, and calculating the <span> [Pb+2]: 
</span><span>
</span><span>Ksp = [Pb++][SCN-]^2 
</span>2.00E-5 = [Pb++](1.00)^2 

<span>[Pb++] = 2.00E-5 M </span>

<span>The mass balance shows that: </span>

<span>[Pb++] = [Pb(SCN)2] </span>

So [Pb(SCN)2] = 2.00E-5 M in 1.00 M KSCN.
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3 years ago
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Calculate the ph of a 0.60 m h2so3, solution that has the stepwise dissociation constants ka1 = 1.5 × 10-2 and 1.82 1.06 1.02 2.
Vsevolod [243]
Missing in your question Ka2 =6.3x10^-8
From this reaction:
 H2SO3 + H2O ↔ H3O+  + HSO3-
by using the ICE table :
                H2SO3     ↔    H3O     +    HSO3- 
intial         0.6                     0                  0
change     -X                      +X                +X
Equ         (0.6-X)                  X                   X

when Ka1 = [H3O+][HSO3-]/[H2SO3]
So by substitution:
1.5X10^-2 = (X*X) / (0.6-X) by solving this equation for X
∴ X = 0.088
∴[H2SO3] = 0.6 - 0.088 = 0.512
[HSO3-] = [H3O+] = 0.088

by using the ICE table 2:
                 HSO3-     ↔   H3O     +     SO3-
initial        0.088              0.088              0
change    -X                      +X                   +X
Equ         (0.088-X)          (0.088+X)          X

Ka2= [H3O+] [SO3-] / [HSO3-]
we can assume [HSO3-] =  0.088 as the value of Ka2 is very small
 6.3x10^-8 = (0.088+X)*X / 0.088
X^2 +0.088 X - 5.5x10^-9= 0 by solving this equation for X
∴X= 6.3x10^-8
∴[H3O+] = 0.088 + 6.3x10^-8
               = 0.088 m ( because X is so small)
∴PH= -㏒[H3O+]
       = -㏒ 0.088 = 1.06 
5 0
3 years ago
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What is 2n^2 rule ( of science)​
lozanna [386]

2n² rule:

This rule is used to determine number of electrons in particular shell.

n=1 means K shell

n=2 means L shell

n=3 means M shell

n=4means N shell

The first K shell can hold upto 2 electrons, L shell can hold up to 8, third M shell can hold up to 18and the fourth N shell can hold upto 32 electrons. This rule of arrangement of electrons according to the shell is known 2n2 rule where n means number of shell.

For example: There is one proton in the nucleus of hydrogen atom, which moves in K shell path. It has no neutron.

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You only need a 2 at the end In front of the NaCl
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2 years ago
What is the temperature difference if 300 cal are used to warm water
PIT_PIT [208]

Answer:

<u>The temperature difference is</u> \frac{300}{m} Kkg^{-1}

Explanation:

The formula that is to used is :

ΔQ=msΔT

<em>where ,</em>

  • <em>ΔQ is the heat supplied in calories = 300cal</em>
  • <em>m is the mass of water taken = m (assumed)</em>
  • <em>ΔT is the change in temperature</em>
  • <em>s is the specific heat of water = 1calK^{-1}Kg^{-1}</em>

ΔT :

\frac{300}{m*1} \\=\frac{300}{m} Kkg^{-1}

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