Add 4H2 in the reactant side, that will give you 4H2O in the product side.
Answer:
Zn(s) + Cu²⁺(aq) ⇒ Zn²⁺(aq) + Cu(s)
Explanation:
Let's consider the molecular single displacement equation between Zn and Cu(NO₃)₂
Zn(s) + Cu(NO₃)₂(aq) ⇒ Zn(NO₃)₂(aq) + Cu(s)
The complete ionic equation includes all the ions and insoluble species.
Zn(s) + Cu²⁺(aq) + 2 NO₃⁻(aq) ⇒ Zn²⁺(aq) + 2 NO₃⁻(aq) + Cu(s)
The net ionic equation includes only the ions that participate in the reaction and insoluble species.
Zn(s) + Cu²⁺(aq) ⇒ Zn²⁺(aq) + Cu(s)
Answer:
Hg2^2+(aq) + 2Cl^-(aq) —> Hg2Cl2(s)
Explanation:
The balanced equation for the reaction is given below:
2NaCl(aq) + Hg2(NO3)2(aq) —> 2NaNO3(aq) + Hg2Cl2(s)
Considering the states of each compound in the reaction, we can see that Hg2Cl2 is in solid form meaning it will precipitate out of the solution
In solution the following occurs:
NaCl —> Na+(aq) + Cl-(aq)
Hg2(NO3)2 —> Hg2^2+(aq) + 2NO3^-(aq)
Combining the two equation together, a balanced double displacement reaction occurs as shown below:
2Na+(aq) + 2Cl-(aq) + Hg2^2+(aq) + 2NO3^-(aq) —> 2Na+2NO3^-(aq) + Hg2^2+2Cl-(s)
From the above we can thus right the insoluble precipitate as
Hg2^2+(aq) + 2Cl^-(aq) —> Hg2Cl2(s)
Answer:
<em>Mass percent composition of K = mass contribution of K/molecular mass of K3Fe(CN)6 x 100% Mass percent composition of K = 117.30 g/mol/329.27 g/mol x 100% Mass percent composition of K = 0.3562 x 100% Mass percent composition of K = 35.62%</em>