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4 years ago

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A hydrogen electron jumps from energy level n = 2 to n = 4 after energy absorption. What will the spectral lines emitted by this

electron look like under a spectroscope?
a. a dark line spectrum
b. white light
c. a continuous spectrum
d. a bright line spectrum

2 answers:

ololo11 [35]4 years ago

3 0

A. a dark line spectrum

Zinaida [17]4 years ago

3 0

I believe the answer is A, but I'm not sure. I would get a second opinion.

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A patient is prescribed 100.0 mg/day of antibiotic for

Rufina [12.5K]

Answer:

70

Explanation:

20 x 5 vials = 100mg

therefore 5 vials required each day.

Two weeks = 14 days

14 days x 5 vials = 70 vials

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3 years ago

Calculate ΔH for the reaction: C(graphite) + 2H 2(g) + 1/2 O 2(g) => CH 3OH(l) Using the following information: C(graphite) +

Alika [10]

Answer:

$\Delta H$ for the given reaction is -238.7 kJ

Explanation:

The given reaction can be written as summation of three elementary steps such as:

$C(graphite)+O_{2}(g)\rightarrow CO_{2}(g)$ $\Delta H_{1}= -393.5 kJ$

$2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l)$ $\Delta H_{2}= (2\times -285.8)kJ$

$CO_{2}(g)+2H_{2}O(l)\rightarrow CH_{3}OH(l)+\frac{3}{2}O_{2}(g)$ $\Delta H_{3}= 726.4 kJ$

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$C(graphite)+2H_{2}(g)+\frac{1}{2}O_{2}(g)\rightarrow CH_{3}OH(l)$

$\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=-238.7 kJ$

4 0

4 years ago

HEY CAN ANYONE PLS ANSWER DIS IN UR OWN WORDS!!!!!

alexandr1967 [171]

Answer:

1. They debated about many things.

2. Greek philosophers debated about things. They did not have a scientific/experiment based approach to studying nature. They did not have tools.

3. Democritus

4. Democritus had the basic idea of atoms, even though he had no experimental evidence to support his thinking.

5. taught that there were substances called atoms and that these atoms made up all material things. The atoms were unchangeable, indestructible, and always existed.

Explanation:

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3 years ago

Helppppppppp!!!!!!!!!

Ksivusya [100]

The answer is C.) Pair it with a hydrogen half-cell

6 0

3 years ago

A sample of an unknown biochemical compound is found to have a percent composition of 45.46 percent carbon, 7.63 percent hydroge

Leona [35]

Answer:

Formular = C₅H₁₁NO₃

Explanation:

The empirical formular is the simplest formular of a compound can have.

We use the steps below to obtain the empirical formular;

Step 1: Obtain the mass of each element present in grams. Element % = mass in g = m.

Carbon = 45.46% = 45.46g

Hydrogen = 7.63% = 7.63g

Nitrogen = 10% = 10g

Oxygen = 100% - (45.46% + 7.63% + 10%) = 36.31% = 36.31g

Step 2: Determine the number of moles of each type of atom present.

Molar amount (M) = m/atomic mass

Carbon = 45.46 / 12 = 3.7883

Hydrogen = 7.63 / 1 = 7.63

Nitrogen = 10 / 14 = 0.7143

Oxygen = 36.91 / 16 = 2.3069

Step 3: Divide the number of moles of each element by the smallest number of moles. Smallest = 0.7143

Carbon = 3.7883 / 0.7143 = 5.3035

Hydrogen = 7.63 / 0.7143 = 10.67

Nitrogen = 0.7143 / 0.7143 = 1

Oxygen = 2.2693 / 0.7143 = 3.1770

Step 4: Convert numbers to whole numbers

Carbon = 5

Hydrogen = 11

Nitrogen = 1

Oxygen = 3

Formular = C₅H₁₁NO₃

3 0

4 years ago