Lead has a different chemistry than most biological metals, but it can mimic some of them, such as calcium, iron, and zinc, because it tends to form 2+ ion like other metals, and these can be formed inside the body. Due to it different chemistry, lead prevents normal functioning of the enzymes it binds to, inhibiting them and poisoning the body.
Gold rarely forms ions, unless under extreme conditions that are not present in the human body. Gold ions, when ingested, are actually very toxic, so gold poisoning is possible. But because gold are so rare, gold poisoning is also a rare phenomenon.
Quantum numbers are used to describe the location of electrons in atoms.
Principal quantum number(n) tells which energy shell the electrons reside in.
The first energy shell n = 1, second energy shell n = 2 and it goes on.
Azimuthal quantum number (l) states which orbital the electron is most likely to reside in. the number of orbitals in an energy shell depends on the principal quantum number. number of orbitals are from 0 to n-1
If l = 0, s orbital
l = 1 , p orbital
l = 2, d orbital
in 2nd energy shell the number of orbitals are 0,1 etc.
5s-
Principal quantum number n = 5
Azimuthal quantum number l = 0
6p
Principal quantum number n = 6
Azimuthal quantum number l = 1
4d
Principal quantum number n = 4
Azimuthal quantum number l = 2
Answer:
C8H17N
Explanation:
Mass of the unknown compound = 5.024 mg
Mass of CO2 = 13.90 mg
Mass of H2O = 6.048 mg
Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:
For carbon, C:
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Mass of C = 12/44 x 13.90 = 3.791 mg
For hydrogen, H:
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H = 2/18 x 6.048 = 0.672 mg
For nitrogen, N:
Mass N = mass of unknown – (mass of C + mass of H)
Mass of N = 5.024 – (3.791 + 0.672)
Mass of N = 0.561 mg
Now, we can obtain the empirical formula for the compound as follow:
C = 3.791 mg
H = 0.672 mg
N = 0.561 mg
Divide each by their molar mass
C = 3.791 / 12 = 0.316
H = 0.672 / 1 = 0.672
N = 0.561 / 14 = 0.040
Divide by the smallest
C = 0.316 / 0.04 = 8
H = 0.672 / 0.04 = 17
N = 0.040 / 0.04 = 1
Therefore, the empirical formula for the compound is C8H17N
<u>We are given:</u>
Mass of NaCl in the given solution = 22.3 grams
Volume of the given solution = 2 L
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<u>Number of Moles of NaCl:</u>
We know that the number of moles = Given mass / Molar mass
Number of moles = 22.3 / 58.44 = 0.382 moles
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<u>Molarity of NaCl in the Given solution:</u>
We know that Molarity of a solution = Moles of Solute / Volume of Solution(in L)
Molarity = 0.382 / 2
Molarity = 0.191 M
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