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olchik [2.2K]
3 years ago
15

A turtle accelerates from a stop at 3m/s/s to the South for 8s. What is the turtle’s final velocity? Show your work and include

the correct units.
Physics
1 answer:
andrey2020 [161]3 years ago
5 0

He's accelerating at 3 m/s² .  That means his speed is increasing by 3 m/s every second.At the end of 8 seconds, his speed is (8 x 3 m/s)  =  24 m/s .He's been moving south for the whole 8 seconds.So at the end of that time, his velocity is                          24 m/s south .

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Which of the following solves a known problem with wind energy?
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Answer:

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5 0
3 years ago
A space rocket is launched and accelerates uniformly to 160 m/s in 4.5 s. Calculate the acceleration of the rocket.​
-BARSIC- [3]

Answer:

<h2>35.56 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

v is the velocity

t is the time

From the question we have

a =  \frac{160}{4.5}  = 35.55555...

We have the final answer as

<h3>35.56 m/s²</h3>

Hope this helps you

6 0
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Kryger [21]

Answer: I have no idea either i need help aswell

Explanation:

4 0
3 years ago
Read 2 more answers
If a certain brand of solar panels is rated at a value of 1.50 KW/m2 , and a person needed to generate 2.50 MJ in an hour, what
alisha [4.7K]

Answer:

A=0.462\ m^2

Explanation:

Power rating of a solar panel is 1.50 KW/m²

It generates 2.50 MJ in an hour.

We need to find the area of this type of solar panel would be needed. The power pertaining to generate this energy is given by :

P=\dfrac{2.5\times 10^6}{1\ h}\\\\P=\dfrac{2.5\times 10^6}{3600\ s}\\\\P=694.44\ W

Let A be the area of the solar panel. It is calculated as follows :

\dfrac{P}{A}=1.5\times 10^3\\\\A=\dfrac{694.44}{1.5\times 10^3}\\A=0.462\ m^2

So, the required area of the solar panel is 0.462\ m^2.

4 0
3 years ago
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