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3 years ago

Which device assists with medical imaging?

Engineering

2 answers:

kirill115 [55]3 years ago

8 0

Answer:

B. Ultrasound machine

Yuliya22 [10]3 years ago

8 0

Answer:

what the problem i can help you

Explanation:

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A solid round bar with a diameter of 2.32 in has a groove cut to a diameter of 2.09 in, with a radius of 0.117 in. The bar is no

Alenkinab [10]

Answer:

nf=1.11 (Goodman criterion)

ny=2.41 (factor of safety for fatigue)

Explanation:

From the table A-20 Deterministic ASTM minimum tensile and yield strengths for HR and CD steels, we have approximately:

Sut=120 kpsi

Sy=66 kpsi

Due Sut<1400 Mpa, the endurance limit is:

$Se=0.5Sut=0.5*120=60 kpsi$

The surface condition modification factor is:

$ka=a(Sut)^{b}=2.7(120)^{-0.265} =0.759$

The effective diameter is:

$de=0.37d=0.37*2.09=0.7733 in$

The size factor is:

$kb=0.879de^{-0.107} =0.879(0.7733)^{-0.107} =0.9$

The endurance limit at critical location is:

$See=ka*kb*kc*kd*kd*ke*kf*Se=0.759*0.9*1*60=40.986 kpsi$

$\frac{D}{d}=\frac{2.32}{2.09} =1.11\\\frac{r}{d}=\frac{0.117}{2.09} =0.056$

From Figure A-15-15 chart, the Kf = 2.1

The notch sensitivity is:

$\sqrt{a}=0.246-3.08(10^{-3})Sut+1.51(10^{-5})Sut^{2}-2.67(10^{-8})Sut^{3}$

$\sqrt{a}=0.246-3.08(10^{-3})(120)+1.51(10^{-5})(120^{2})-2.67(10^{-8})(120^{3})=0.048$

$q=\frac{1}{1+\frac{\sqrt{a} }{\sqrt{r} } }=\frac{1}{1+\frac{0.048}{\sqrt{0.117} } }=0.877$

The fatigue stress is:

$Kf=1+q(Kt-1)=1+0.877(2.1-1)=1.96$

The moment of inertia is:

$I=\frac{\pi }{64} d^{4}=\frac{\pi }{64} (2.09^{4})=0.936 in^{4}$

The maximum stress is:

$omax=\frac{M*c}{I}=\frac{25000*\frac{2.09}{2} }{0.936} =27911.32 psi=27.911 kpsi$

The mean stress is:

$om=Kf\frac{omax+omin}{2} =1.96\frac{27.911+0}{2}=27.35 kpsi$

The alternate stress is:

$oa=Kf|\frac{omax-omin}{2}|=27.35 kpsi$

The fatigue factor using Goodman is:

$\frac{1}{nf}=\frac{oa}{See}+\frac{om}{Sut}\\\frac{1}{nf}=\frac{27.35}{40.986}+\frac{27.35}{120}$

nf=1.11

the factor of safety is:

$ny=\frac{Sy}{omax}=\frac{66}{27.35} =2.41$

4 0

4 years ago

Given a series of numbers as input, add them up until the input is 10 and print the total. Do not add the final 10. For example,

valentinak56 [21]

Answer:

Explanation:

The question talks about a given program to which you input a set of numbers. Once you input number 10, the program stops receiving inputs and adds the numbers you previously inputed, except for the final 10 which only works as a stopping signal. So, imagine you are working on the program and input the numbers 8, 3, 11 and 10 consecutively. Once you input the 10, the program immediately adds the previous numbers: 8+3+11=22.

So the output should be 22.

4 0

4 years ago

1. A gas pressure difference is applied to the legs of a U-tube manometer filled with a liquid with S = 1.5. The manometer readi

julia-pushkina [17]

Answer:

1) The pressure difference is 4.207 kilopascals.

2) 2.5 pounds per square inch equals 5.093 inches of mercury and 5.768 feet of water.

Explanation:

1) We can calculate the gas pressure difference from the U-tube manometer by using the following hydrostatic formula:

$\Delta P = \frac{S\cdot \rho_{w}\cdot g \cdot \Delta h}{1000}$ (Eq. 1)

Where:

$S$ - Relative density, dimensionless.

$\rho_{w}$ - Density of water, measured in kilograms per cubic meter.

$g$ - Gravitational acceleration, measured in meters per square second.

$\Delta h$ - Height difference in the U-tube manometer, measured in meters.

$\Delta P$ - Gas pressure difference, measured in kilopascals.

If we know that $S = 1.5$ , $\rho_{w} = 1000\,\frac{kg}{m^{3}}$ , $g = 9.807\,\frac{m}{s^{2}}$ and $\Delta h = 0.286\,m$ , then the pressure difference is:

$\Delta P = \frac{1.5\cdot \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.286\,m)}{1000}$

$\Delta P = 4.207\,kPa$

The pressure difference is 4.207 kilopascals.

2) From Physics we remember that a pound per square unit equals 2.036 inches of mercury and 2.307 feet of water and we must multiply the given pressure by corresponding conversion unit: ( $p = 2.5\,psi$ )

$p = 2.5\,psi\times 2.037\,\frac{in\,Hg}{psi}$

$p = 5.093\,in\,Hg$

$p = 2.5\,psi\times 2.307\,\frac{ft\,H_{2}O}{psi}$

$p = 5.768\,ft\,H_{2}O$

2.5 pounds per square inch equals 5.093 inches of mercury and 5.768 feet of water.

4 0

4 years ago

Choose the person who best completes each statement.

victus00 [196]

The exercise is about finding the missing medical terms from the list below.. See the sentences below for the missing words.

<h3>What are the completed sentences?</h3>

The outbreak and spread of epidemic diseases, such as swine flu, are tracked by a <u>Public Health Surveillance Team.</u>
The person who would use equipment to show an image of a baby before birth is a <u>Diagnostic Medical Sonographer.</u>
The education to become a <u>Medical Practitioner</u> requires more than four years of college.
When a water source becomes contaminated with an illness-causing bacteria, a <u>Microbiologist</u> could be brought in to study how to get rid of the microorganisms.

Learn more about medical terms at;
brainly.com/question/759368
#SPJ1

7 0

2 years ago

Read 2 more answers

in a vehicle you're servicing the fuel pressure drops rapidly when the engine is says that one or more turned off. Technician a

expeople1 [14]

Answer:

Both Technicians A and B are correct

Explanation:

If the fluid pressure will decrease quickly in a car when the ignition says that one or more has been switched off. One or two could be leaking or the source could be a faulty check mechanism in the catalytic converter.

3 0

4 years ago