Answer: Coefficient= 0.35 per day
Explanation:
To find the bio degradation reaction rate coefficient, we have
k= 
Here, the C lagoon= 20 mg/L
Q in= Q out= 8640 m³/d
C in= 100 mg/L
C out= 20 mg/L
V= 10 ha* 1* 10
V= 10⁵ m³
So, k= 
k= 0.35 per day
R01= 14.1 Ω
R02= 0.03525Ω
<h3>Calculations and Parameters</h3>
Given:
K= E2/E1 = 120/2400
= 0.5
R1= 0.1 Ω, X1= 0.22Ω
R2= 0.035Ω, X2= 0.012Ω
The equivalence resistance as referred to both primary and secondary,
R01= R1 + R2
= R1 + R2/K2
= 0.1 + (0.035/9(0.05)^2)
= 14.1 Ω
R02= R2 + R1
=R2 + K^2.R1
= 0.035 + (0.05)^2 * 0.1
= 0.03525Ω
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Answer:
3A
Explanation:
Using Ohms law U=I×R solve for I by I=U/R
The watts that are consumed is 80 watts.
<h3>What power factor?</h3>
The term power factor has to do with the measure of the efficiency of the use of energy. Recall that power is defined as the rate of doing work. The magnitude of the power factor shows the extent to which the power is used.
Now, to obtain the watts are consumed in a circuit having a power factor of 0. 2 if the input is 100 vac at 4 amperes we have; V × I × PF = 100V × 4A × 0.2 = 80 watts.
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Explanation:
a) The total volume equals the sum of the volumes.
500 = x + y
The total octane amount equals the sum of the octane amounts.
89(500) = 87x + 92y
44500 = 87x + 92y
b) desmos.com/calculator/ekegkzllqx
As x increases, y decreases.
c) Use substitution or elimination to solve the system of equations.
44500 = 87x + 92(500−x)
44500 = 87x + 46000 − 92x
5x = 1500
x = 300
y = 200
The required volumes are 300 gallons of 87 gasoline and 200 gallons of 92 gasoline.
