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2 years ago

14

Why doesn't any one give as many points as i do for random questions on brainly

2 answers:

Pani-rosa [81]2 years ago

5 0

Answer:

i think its cuz they dont want to like lose points if they do they cant ask their doubts i just think this is why thx hope you have a beautiful day

Explanation:

erastova [34]2 years ago

4 0

good question i like to give about 20. i think people just are cheapskates for most of their time on this planet. didnt need the 50 though but thanks.

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52 points+Brainliest for correct answer

pentagon [3]

Divide by 6 and divide the caw of squaw squaw

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2 years ago

A circular pipe of 25-mm outside diameter is placed in an airstream at 25 °C and 1-atm pressure. The air moves in cross flow ove

Scrat [10]

Answer: a) Fd = 3.24 N/m

b) Q = 520 w/m

Explanation: please find the attached files for the solution

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3 years ago

Calculate KI for a rectangular bar containing an edge crack loaded in three-point bending where P=35.0 kN, W=50.8 mm, B=25 mm, a

Katyanochek1 [597]

Answer:

$K_{I}=5.21 MPa\sqrt{m}$

Explanation:

given data

Load P = 35 kN

Width of bar W = 50.8 mm

Breadth of bar B = 25 mm

Ratio of crack length to width α = a/W = 0.2

solution

we get here KI for a rectangular bar that is express as

$K_{I} = \frac{6P}{BW}Y\sqrt{\pi a}$ ................................1

here Y is the geometrical function

so

Y = $\frac{1.12+\alpha (3.43\alpha -1.89)}{1-0.55\alpha}$

Y = $\frac{1.12+0.2(3.43\times 0.2-1.89)}{1-0.55\times 0.2}$

Y = $\frac{0.8792}{0.89}$

Y = 0.9878

so put here value in equation 1

$K_{I} = \frac{6\times 35\times 10^{3}}{0.025\times 0.0508}\times 0.9878\times \sqrt{3.1415\times (0.2\times 0.0508)}$

$K_{I} = 165354.33\times 10^{3}\times 0.9878\times 0.0319$

$K_{I}$ = 5210.45 × 10³ $Pa\sqrt{m}$

$K_{I}$ = 5.21 MPa $\sqrt{m}$

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3 years ago

Ben leads a team of a few engineers at a robotics firm. A couple of them would like to improve their skills by taking additional

Anit [1.1K]

Answer:

i dont know

Explanation:

4 0

3 years ago

A fluid has a viscosity of 13 P and a specific gravity of 0.94. Determine the kinematic viscosity of this fluid in units of ft²/

OlgaM077 [116]

Answer:

kinematic viscosity is 0.0149 ft²/s

Explanation:

given data

specific gravity S = 0.94

density ρ = 0.94 × 1000

viscosity μ = 13 Poise = 1.3 Pa-sec

we know 1 poise = 0.1 pas

to find out

kinematic viscosity

solution

we will apply here Kinematic viscosity formula that is

kinematic viscosity = $\frac{\mu}{\rho}$ ..................1

put here value in equation 1

and here ρ is density and μ is viscosity

kinematic viscosity = $\frac{1.3}{0.94*1000}$

kinematic viscosity = 1.382978 × $10^{-3}$ m³/s

so kinematic viscosity is 0.0149 ft²/s

3 0

3 years ago