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1 year ago

Why doesn't any one give as many points as i do for random questions on brainly

Engineering

2 answers:

Pani-rosa [81]1 year ago

5 0

Answer:

i think its cuz they dont want to like lose points if they do they cant ask their doubts i just think this is why thx hope you have a beautiful day

Explanation:

erastova [34]1 year ago

4 0

good question i like to give about 20. i think people just are cheapskates for most of their time on this planet. didnt need the 50 though but thanks.

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MrRa [10]

That’s too hard for me lol oof

3 0

2 years ago

Which of the following are three criteria for creating measurable product attributes?

Vinil7 [7]

Answer:

it A

Explanation:

8 0

2 years ago

Read 2 more answers

A piston-cylinder assembly contains 0.5 lb of water. The water expands from an initial state where p1 = 40 lbf/in.2 and T1 = 300

VARVARA [1.3K]

Answer:

W = 31.393 Btu

Explanation:

given data

piston-cylinder assembly contains water = 0.5 lb

p1 = 40 lbf/in² = 40 × 144 lbf/ft²

T1 = 300° F

p2 = 14.7 lbf/in² = 14.7 × 144 lbf/ft²

pv 1.2 = constant.

solution

we use here superheated table A 4E to get value for p1 = 40 and t = 300

v1 = 11.04 ft³/lbm

so we know

$P_2 \times V_2^{1.2} = P_1 \times V_1^{1.2}$ ,...............1

$14.7 \times V_2^{1.2} = 40 \times (11.04)^{1.2}$

solve it we get

v2 = 25.425 ft³/lbm

and here

W = $(\frac{P_1V_1 - P_2V_2}{n-1}) m$ ...............2

put here value we get

W = $(\frac{40\times 144\times (11.04) -14.7 \times 144\times (25.425) }{1.2-1})0.5$

solve it we get

W = 31.393 Btu

5 0

2 years ago

The Air Force One (Boeing 747-200) has a long-range mission takeoff gross load 833,000 pounds (Ibm). What is Air Force One's tak

Ahat [919]

Answer:

The mass in:

1) Grams = $377765.5\times 10^{3}grams$

2) Kilograms = $377765.5kilograms$

3)Tonnes = $377.7655tonnes$

4) Megatonnes = $0.378megatonnes$

Explanation: The given mass of the aircraft in pounds is 833,000 pounds.

Part 1)

Since we know that 1 pound equals 453.5 grams thus by ratio we have

833,000 pounds = $833000lb\times 453.5\frac{g}{lb}=377765.5\times 10^{3}grams$

Part 2)

Since we know that 1000 grams equals 1 kilogram

thus the above mass in kilograms equals $\frac{377765.5\times 10^{3}}{1000}=377765.5kg$

Part 3)

Since there are 1000 kilograms in 1 tonne

thus the given mass is converted into tonnes as

$mass_{tonnes}=\frac{377765.5kg}{1000}=377.765tonnes$

Part 4)

Since 1 Mega tonne(Mton) equals 1000 tonnes thus the given mass is converted into mega tonnes as

$mass_{M\cdot tonn}=\frac{377.7655tonnes}{1000}=0.378Megatonnes$

4 0

2 years ago

For the following pairs of sinusoidal time functions, determine which one leads/lags and by how much. (a) ????1(????)=4sin(6π×10

rjkz [21]

Answer:

The question is incomplete, the complete question is given below

"For the following pairs of sinusoidal time functions, determine which one leads/lags and by how much. (a) V1(t) =4sin(6π×10^4t+60°)V and V(t)2=2cos(6π×10^4t−20°)V. (b) V(t)=10cos(400t−75°) V and I(t)=4sin(400t+30°) A.

Answer

A. V2(t) leads V1(t) by 10°

B. I(t) leads V(t) by 15°

Explanation:

First we express the relationship between sine and cosine of a value.

The expression is giving below Cos (wt) =Sin(wt+90)

Hence for the equations above, we write

a. We can v(t) as

V1(t)=4Sin(6π*10^4+90°-30°)

V1(t)=4Cos(6π*10^4-30°)

Comparing to

V2(t)=4Cos(6π*10^4-20°)

Comparing the angle, we notice that V2(t) leads V1(t) by 10°

b. We can write the current wave form as

I(t)=4sin(400t+90°-60°)

I(t)=4Cos(400t-60°)

If we compare with V(t)=10cos(400t−75°)

I.e 4Cos(400t-60°)=10cos(400t−75°)

We can conclude that I(t) leads V(t) by 15°

4 0

2 years ago