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kodGreya [7K]
3 years ago
8

Name two air pollutants that bioaccumulate

Chemistry
1 answer:
Andreyy893 years ago
6 0

Answer:

Methane

Carbon Dioxide

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C6H12O6 + 6O2 → 6CO2 + ? H2O + energy<br> Whats the answer? I really don't know,
Ket [755]

Answer:  C. 6

Explanation:

According to the Law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical reaction for photosynthesis is :

C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O+energy

Thus the coefficient of water is 6.

4 0
3 years ago
Study the following two reactions. Select all that apply.
NISA [10]
Its B and D
...............................................................

7 0
3 years ago
Read 2 more answers
prease tell me the answer. When a liquid changes to a gas below the surface of a liquid as well as at the surface, it is called
Anton [14]
Its called freezing, the change from a liquid to a gas is called vaporization
6 0
4 years ago
Read 2 more answers
11 Which substance can not be broken down by a chemical change?
Rus_ich [418]
(2) Arsenic. It is an element and elements are chemically the simplest units and cannot be broken down by any chemical change.
4 0
3 years ago
If the pressure on the surface of water in the liquid stato
Novosadov [1.4K]

The water will boil at C) 80°C

<h3>Further explanation</h3>

Given

Vapour pressure of water = 47 kPa

Required

Boiling point of water

Solution

We can use the Clausius-Clapeyron equation :

\tt ln(\dfrac{P_1}{P_2})=\dfrac{-\Delta H_{vap}}{R}(\dfrac{1}{T_1}-\dfrac{1}{T_2})

Vapour pressure of water at boiling point 100°C=101.325 kPa

ΔH vap for water at 100°C=40657 J/mol

R = 8.314 J/mol K

T₁=boiling point of water at 101.325 kPa = 100+273=373 K

Input given values :

\tt ln\dfrac{101.325}{47}=\dfrac{-40657}{8.314}(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\0.7682=4890.1852(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\0.0001571=(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\\dfrac{1}{T_2}=0.00283\rightarrow T_2=353~K=80^oC

6 0
3 years ago
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