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Mandarinka [93]
3 years ago
7

What is the pattern in the charge for elements in each group on the periodic table?

Chemistry
1 answer:
madreJ [45]3 years ago
5 0
( besides the transition metals) the group shows charge with...
1, +1 charge ( loses to group 17)
2, +2 charge
13, +3 charge
14, ±4 charge ( depends on if this is a metal or nonmetal( metalloids are classified by which side of the staircase))
15, -3 charge
16, -2 charge
17, -1 charge ( gains from group one ( halogens(17) and alkali metals (1) are highly reactive).
18, no charge (noble gasses are always full with valence electrons, thus have no charge and rarely form compounds.)
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Silver is not a compound. It's a mixture
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Can someone help me with #35,37,39,41 please
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35 b.
37 h
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4 0
3 years ago
Infrared (IR) and Nuclear Magnetic Resonance (NMR) are two spectroscopic techniques you've encountered in organic chemistry I, C
zalisa [80]

Answer:

The solution to this question can be defined as follows:

Explanation:

Please find the attached file for the solution:

8 0
3 years ago
I need help on both a and b of question 1
marishachu [46]

Answer:

(a) -0.00017 M/s;

(b) 0.00034 M/s

Explanation:

(a) Rate of a reaction is defined as change in molarity in a unit time, that is:

r = \frac{\Delta c}{\Delta t}

Given the following reaction:

2 N_2O_5 (g)\rightleftharpoons 4 NO_2 (g) + O_2 (g)

We may write the rate expression in terms of reactants firstly. Since reactants are decreasing in molarity, we're adding a negative sign. Similarly, if we wish to look at the overall reaction rate, we need to divide by stoichiometric coefficients:

r = -\frac{\Delta [N_2O_5]}{2 \Delta t}

Reaction rate is also equal to the rate of formation of products divided by their coefficients:

r = \frac{\Delta [NO_2]}{4 \Delta t} = \frac{\Delta [O_2]}{\Delta t}

Let's find the rate of disappearance of the reactant firstly. This would be found dividing the change in molarity by the change in time:

r_{N_2O_5} = \frac{0.066 M - 0.100 M}{200.00 s - 0.00 s} = -0.00017 M/s

(b) Using the relationship derived previously, we know that:

-\frac{\Delta [N_2O_5]}{2 \Delta t} = \frac{\Delta [NO_2]}{4 \Delta t}

Rate of appearance of nitrogen dioxide is given by:

r_{NO_2} = \frac{\Delta [NO_2]}{\Delta t}

Which is obtained from the equation:

-\frac{\Delta [N_2O_5]}{2 \Delta t} = \frac{\Delta [NO_2]}{4 \Delta t}

If we multiply both sides by 4, that is:

-\frac{4 \Delta [N_2O_5]}{2 \Delta t} = \frac{\Delta [NO_2]}{\Delta t}

This yields:

[tex]r_{NO_2} = \frac{\Delta [NO_2]}{\Delta t} = -2\frac{\Delta [N_2O_5]}{ \Delta t} = -2\cdot (-0.00017 M/s) = 0.00034 M/s[tex]

5 0
3 years ago
The compound barium acetate is a strong electrolyte. Write the reaction when solid barium acetate is put into water.
Ipatiy [6.2K]

Answer:

Explanation:

If any doubt comment your question or what needs clarification.

4 0
2 years ago
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