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irina [24]
3 years ago
7

The potential difference across a piece of wire is 2.1 v the current in the wire is 0.30 a calculate the resistance of the wire

in ohms
Physics
1 answer:
IrinaVladis [17]3 years ago
8 0

Answer:

<h2>7Ω</h2>

Explanation:

Given:

V = 2.1 v

I = 0.30 A

R = Unknown

Solution:

R = V / I

= 2.1V / 0.30A

= 7Ω

Answer:

7Ω is the resistance of the wire in ohms

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calculate the electric field strength between two parallel plates separated by 0.50 cm, across which is a potential of 12 volts.
Alexxandr [17]
Formula for Electric Field strength , E =  V/d

where V = Voltage in volts, and d = distance of separation in meters.

d = 0.5 cm = 0.005 m,    V = 12 V

E = V/d =  12 / 0.005

E = 2400

Electric Field Strength = 2400 Volts/meter 
3 0
3 years ago
The process of how rocks can tell us how old the earth is
Ludmilka [50]
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7 0
3 years ago
A supply bag is dropped from a rescue plane. After the bag falls for 3.2 seconds , what is the velocity of the bag?
loris [4]

Answer: -31.36 m/s

Explanation:

This is a problem of motion in one direction (specifically vertical motion), and the equation that best fulfills this approach is:

V_{f}=V_{o}+a.t  (1)

Where:

V_{f} is the final velocity of the supply bag

V_{o}=0 is the initial velocity of the supply bag (we know it is zero because we are told it was "dropped", this means it goes to ground in free fall)

a=g=-9.8m/s^{2} is the acceleration due gravity (the negtive sign indicates the gravity is downwards, in the direction of the center of the Earth)

t=3.2s is the time

Knowing this, let's solve (1):

V_{f}=0+(-9.8m/s^{2})(3.2s)  (2)

Finally:

V_{f}=-31.36m/s  Note the negative sign is because the direction of the bag is downwards as well.

8 0
3 years ago
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3 0
3 years ago
a crate is being lifted into a truck. if it is moved with a 2470n force and 3650 j of work is done , then how far is the crate b
SVEN [57.7K]

Answer:

The crate was being lifted by a height of 1.48 meters.

Explanation:

In an attempt o move a crate;

Force applied = 2470 N

Work done by the force = 3650 J

We know that the work done is defined as the force used to move an object to a distance.

Given the Force used and the work done by that Force, we need to find out the distance the crate was lifted to.

Work done is defined as:

Work = Force*distance covered in the direction of the force

3650 = 2470*distance

distance = 3650/2470

distance = 1.48 meters

4 0
3 years ago
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