Answer:
i think the answer is constant
The answer is 266. Hope that helps!
Incomplete question.The complete question is here
Determine the torque applied to the shaft of a car that transmits 225 hp and rotates at a rate of 3000 rpm.
Answer:
Torque=0.51 Btu
Explanation:
Given Data
Power=225 hp
Revolutions =3000 rpm
To find
T( torque )=?
Solution
As

As force moves an object through a distance, work is done on the object. Likewise, when a torque rotates an object through an angle, work is done.
So

A man pulls on a box with 50 N of applied force while another man pushes on the box from the opposite direction with 60 N of applied force. The box will stand still.
TRUE.
Answer: p = - {1/2} , q = {1/2}
Explanation: The frequency of oscillation of a pendulum is given as
F = 1/2π *√{l/g}
Where √ is square root
l is lenght
g is acceleration due to gravity
But
F = 1/T
Where T is the period of Oscillation
Making T subject of formula we have
T= 1/F
T = 2π√{g/l}
Here the power on l is -[1/2]= p
Also,
Power on g is 1/2 =q
All because of the square root.