Answer:
Por lo tanto, la presión del ozono es:
Explanation:
Podemos usar la ecuacion de los gases ideales;
(1)
Tenemos:
El volumen V = 224 dm³ = 224 L
La temperatura T = 51.09 C = 324.09 K
La masa es m = 4.561 kg
Lo necesitamos ahora es calvular n que es el numero de moles;
recordemos que el peso molecular del ozono M = 48 g/mol.

Finalmente, usando la ecuacion 1 despejamos la presion P
Por lo tanto, la presion del ozono es:
Espero te haya ayudado!
Coulombs law says that the force between any two charges depends on the amount of charges and distance between them. This force is directly proportional to the magnitude of the two charges and inversely proportional to the distance between them.

where
are charges,
is the distance between them and k is the coulomb constant.
case 1:

case 2

case 3:

Comparing the 3 cases:
The maximum potential force according to coulombs law is between -1 charge and +3 charge separated by a distance of 100 pm.
Answer:
Explanation:
The standard equation of the sinusoidal wave in one dimension is given by

Here, A be the amplitude of the wave
λ be the wavelength of the wave
v be the velocity of the wave
Φ be the phase angle
x be the position of the wave
t be the time
this wave is travelling along positive direction of X axis
The frequency of wave is f which relates with velocity and wavelength as given below
v = f x λ
The relation between the time period and the frequency is
f = 1 / T.
Answer:
THES IS NOT
Explanation:
THIS PAPAER IS A FAKE PAPAER BEACISE POGI TALAGA AKO
Answer:
Explanation:
Given
Wheels are rotating with constant angular velocity let say 
Presence of constant angular velocity show that there is no angular acceleration thus there is no tangential acceleration.
But any particle on the rim will experience a constant acceleration towards center called centripetal acceleration.
(a) yes, there will be tangential velocity which is given by

where r=radial distance from center
(b)tangential acceleration
there would be no tangential acceleration as velocity is constant
(c)centripetal acceleration
Yes, there will be centripetal acceleration given by
