Question

determine the molecular formula of the compound with an empirical formula of CH and a molar mass of 78.110g/mol

Answer 1

Answer:

$C_{6} H_{6}$

Explanation:

First, find the mass of empirical formula, CH. 12.01 g/mol is for carbon, and 1.008 g/mol is for hydrogen. 12.01+1.008=13.018 G/mol CH. Divide 78.110 G/mol by 13.018 g/mol. You get approximately 6. Multiply that by the subscript of each element. 6(CH)=

$C_{6} H_{6}$