To solve this problem it is necessary to apply the concepts related to frequency as a function of speed and wavelength as well as the kinematic equations of simple harmonic motion
From the definition we know that the frequency can be expressed as
Where,
Therefore the frequency would be given as
The frequency is directly proportional to the angular velocity therefore
Now the maximum speed from the simple harmonic movement is given by
Where
A = Amplitude
Then replacing,
Therefore the maximum speed of a point on the string is 3.59m/s
the weight of the balloon is .030 * 10 = 0.3 N
the weight of the gas of volume v is 0.54*10 N
The lifting force of a volume of v m³ of displaced air is 1.29v N
so, we need
1.29*10*v = 0.3 + 0.54*10*v
or
1.29v = 0.03+0.54v
Answer:
The farther star will appear 4 times fainter than the star that is near to the observer.
Explanation:
Since it is given that the luminosity of the 2 stars is same thus they radiate the same energy per unit time
Consider a spherical wave front of energy 'E' that leaves both the stars (Both radiate 'E' as they have same luminosity)
This Energy is spread over the whole surface area of sphere Thus when the wave front is at a distance 'r' the energy per unit surface area is given by
For the star that is twice away from the earth the distance is '2r' thus we will receive an energy given by
Hence we sense it as 4 times fainter than the nearer star.
Yes , increased tension suggests increased molecular attraction between the molecules of the ropes which affect the increase in the speed of wave.
Well, one of the theories was that Charles darwin proved that theory evolution is real so that one theory.
