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FrozenT [24]
3 years ago
5

If you drop something from low height is it faster

Physics
1 answer:
JulijaS [17]3 years ago
8 0

Faster to hit the ground because if so yes?

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Why do you think we cannot use a common fuel like diesel or gasoline for space travel ?
Ede4ka [16]

Answer:

Explanation:

it take oxygen in the atmosphere to burn it... in space there isn't any air  :0

5 0
2 years ago
On a highway curve with a radius of 46 meters, the maximum force of static friction that can act on a 1,200 kg car going around
Mekhanik [1.2K]

Answer:

v\approx 16.956\,\frac{m}{s}

Explanation:

The motion of the vehicule on a highway curve can be modelled by the following equation of equilibrium:

\Sigma F = f = m\cdot \frac{v^{2}}{R}

The maximum speed is:

v = \sqrt{\frac{f\cdot R}{m} }

v = \sqrt{\frac{(7500\,N)\cdot (46\,m)}{1200\,kg} }

v\approx 16.956\,\frac{m}{s}

7 0
3 years ago
Roughly to what height would a 5 kg stone need to be raised in order to have the same stored energy as the energy stored in the
hoa [83]

8.16m is the required height, a 5kg stone need to be raised.

One sort of potential energy is gravitational potential energy, which is equal to the product of the object's mass (m), the gravitational acceleration (g), and the object's height (h) as measured in relation to the ground's surface (the body).

We obtain the formula by considering the work done in raising a mass m through a height h.

Work in elevating mass m through height h is equal to force times distance.

The force must be greater than the mass m's weight, hence F = mg.

Work done = mgh = gravitational potential energy

Energy =  Mass of the object × gravitational acceleration × height.

Mass of the stone = 5kg

Equating ;

∴ 400 J = 5 kg × 9.8 m/s² × height

  Height = 8.16 m

Therefore, 8.16m is the required height.

Learn more about energy here:

brainly.com/question/1242059

#SPJ1

8 0
2 years ago
How could you record the number 4000 and report 2 significant figures?
yawa3891 [41]

Explanation:

Write in scientific notation.

4000 = 4.0×10³

5 0
3 years ago
Based on the replacement reaction, what would the products of the reaction be?
cricket20 [7]

Answer:

\rm Be(OH)_2 and \rm (NH_4)_2 SO_4. The missing ion would be \rm OH^{-}.

Explanation:

In a double replacement reaction, two ionic compounds exchange their ions to produce two different ionic compounds.

In this question, the two ionic compounds are:

  • \rm BeSO_4, and
  • \rm NH_4 OH.

In particular,

  • \rm BeSO_4 is made up of \rm Be^{2+} ions and \rm {SO_4}^{2-} ions, while
  • \rm NH_4 OH is made up of \rm {NH_4}^{+} ions and \rm OH^{-} ions.

In a binary ionic compound, cations (positive ions) can only bond to anions (negative ions.)

  • \rm Be^{2+} is a cation. In \rm BeSO_4, \rm Be^{2+} was bounded \rm {SO_4}^{2-} anions. During the reaction, it bonds with \rm OH^{-} anions to produce \rm Be(OH)_2.
  • \rm {NH_4}^{+} is also a cation. In \rm NH_4 OH, \rm {NH_4}^{+} was bounded to \rm OH^{-} ions. During the reaction, it bonds with \rm {SO_4}^{2-} anions to produce \rm (NH_4)_2 SO_4.

Hence, the two products will be \rm Be(OH)_2 and \rm (NH_4)_2 SO_4.

Note that charges on the ions must balance. For example, a \rm Be^{2+} ion carries twice as much charge as an \rm {NH_4}^{+} ion. As a result, each \rm Be^{2+} ion would bond with twice as many \rm OH^{-} ions as \rm {NH_4}^{+} would in \rm NH_4 OH.

4 0
3 years ago
Read 2 more answers
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