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3 years ago

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Two large, parallel, metal plates carry opposite charges of equal magnitude. They are separated by a distance of 50.0 mm , and t

he potential difference between them is 365 V . Part A What is the magnitude of the electric field (assumed to be uniform) in the region between the plates

1 answer:

givi [52]3 years ago

4 0

Explanation:

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Six artificial satellites circle a space station at constant speed. The mass m of each satellite, distance L from the space stat

nikklg [1K]

Answers:

a) $T_{2}>T_{5}>T_{1}>T_{3}=T_{6}>T_{4}$

b) $a_{4}>a_{6}>a_{1}>a_{3}>a_{5}>a_{2}$

Explanation:

a) Since we are told the satellites circle the space station at constant speed, we can assume they follow a uniform circular motion and their tangential speeds $V$ are given by:

$V=\omega L=\frac{2\pi}{T} L$ (1)

Where:

$\omega$ is the angular frequency

$L$ is the radius of the orbit of each satellite

$T$ is the period of the orbit of each satellite

Isolating $T$ :

$T=\frac{2 \pi L}{V}$ (2)

Applying this equation to each satellite:

$T_{1}=\frac{2 \pi L}{V_{1}}=261.79 s$ (3)

$T_{2}=\frac{2 \pi L}{V_{2}}=1570.79 s$ (4)

$T_{3}=\frac{2 \pi L}{V_{3}}=196.349 s$ (5)

$T_{4}=\frac{2 \pi L}{V_{4}}=98.174 s$ (6)

$T_{5}=\frac{2 \pi L}{V_{5}}=785.398 s$ (7)

$T_{6}=\frac{2 \pi L}{V_{6}}=196.349 s$ (8)

Ordering this periods from largest to smallest:

$T_{2}>T_{5}>T_{1}>T_{3}=T_{6}>T_{4}$

b) Acceleration $a$ is defined as the variation of velocity in time:

$a=\frac{V}{T}$ (9)

Applying this equation to each satellite:

$a_{1}=\frac{V_{1}}{T_{1}}=0.458 m/s^{2}$ (10)

$a_{2}=\frac{V_{2}}{T_{2}}=0.0254 m/s^{2}$ (11)

$a_{3}=\frac{V_{3}}{T_{3}}=0.4074 m/s^{2}$ (12)

$a_{4}=\frac{V_{4}}{T_{4}}=1.629 m/s^{2}$ (13)

$a_{5}=\frac{V_{5}}{T_{5}}=0.101 m/s^{2}$ (14)

$a_{6}=\frac{V_{6}}{T_{6}}=0.814 m/s^{2}$ (15)

Ordering this acceerations from largest to smallest:

$a_{4}>a_{6}>a_{1}>a_{3}>a_{5}>a_{2}$

4 0

2 years ago

A force vector points due east and has a magnitude of 140 newtons. A second force is added to . The resultant of the two vectors

ale4655 [162]

Answer:

(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East

(b) When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West

Explanation:

Given;

a force vector points due east, $F_1$ = 140 N

let the second force = $F_2$

let the resultant of the two vectors = F

(a) When the resultant force is pointing along east line

the second force must be pointing due east

$F = F_1 + F_2\\\\F_2 = F - F_1\\\\F_2 = 420 \ N - 140 \ N\\\\F_2 = 280 \ N$

$F_2 = 280 \ East$

(b) When the resultant force is pointing along west line

the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.

$F = F_2 - F_1\\\\F_2 = F + F_1\\\\F_2 = 420 \ N + 140 \ N\\\\F_2 = 560 \ N$

$F_2 = 560 \ West$

8 0

2 years ago

A point charge q1q1 is held stationary at the origin. A second charge q2q2 is placed at point aa, and the electric potential ene

Yuri [45]

Explanation:

The given data is as follows.

$U_{a} = 5.4 \times 10^{-8} J$

$W_{/text{a to b}} = -1.9 \times 10^{-8} J$

Electric potential energy ( $U_{b}$ ) = ?

Formula to calculate electric potential energy is as follows.

$U_{b} = U_{a} - W_{/text{a to b}}$

= $5.4 \times 10^{-8} J - (-1.9 \times 10^{-8} J)$

= $7.3 \times 10^{-8} J$

Thus, we can conclude that the electric potential energy of the pair of charges when the second charge is at point b is $7.3 \times 10^{-8} J$ .

6 0

3 years ago

A bungee cord has a spring constant of 82.5 N/m. After jumping, a person oscillates with a period of 7.50 s. What is the mass of

Arada [10]

Answer:

Explanation:

T = 2π √ (m/k)

T / 2π = √ (m/k)

T√k = 2π √m

(T√k) / 2π = √m

( (T√k) / 2π)^2 = m

m = ( (7.5√82.5) / 2π)^2

m = 117.66 Kg

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=help%20%5C%3A%20mo%20%5C%3A%20ako%20%5C%3A%20please.." id="TexFormula1" title="help \: mo \: a

morpeh [17]

bentar mo numpang cerita nih

jadi gini

eist yg takut cerita horor Jan di baca

awokawokawok

ok lanjut ya dek ke cerita nya :)

jadi gini di jalan,jalan lalu lintas di kampung,,,,em kyk gini,,,hmm...... kyk mana ku ceritakan ya dek,,,,bingung aku soalnya,,,,,hmm....kyk gini lah,,,,,,,,jalan ini di tengah² kebun/ladang nah kan,,,,, sebenarnya ada dua jalan mo pergi keluar masuk dari kampung ku ke kampung tetanga jadi pejalan kaki lebih suka lewat jalan tikus,,,,,yg punya mobil,kereta/motor,sepeda lewat jalan yg horornl itu yg kubilng tadi itu......,,,,nah,,,,,aku sama kawan²ku lewat jalan yg horor ini,,,,,,nah ngk nyangka ku lihat sosok putih,,,,y aku masih berpikir itu ngk bener ,,,,,trussss dua hari kemudian aku mo pergi ke kampung tetanga pake sepeda,,,,aneh ny sepeda aku berat dan,,,da-dan aku lihat sosok putih itu lagi ,,,aku jadi ngebut deh ,,,,Untung aja aku ngk jatuh ,,,,,klw di bilang suruk² ,,,setiap jalan aku ntah sama siapa² ttp ku lihat sosok putih itu,,,,nah ketika sore² aku jalan sama temen ku,,,,,eh ku lihat lagi,,,,aku penasaran aku aja deh temen ku buat nengok,,,sosok putih itu,,,,ngk nyangka sosok putih itu udh ngk ada ,,,,aneh ngab :v

dah lah sampe disini aja dulu ya dek

byee byee

$............. ... .$

6 0

2 years ago