Explanation:
The 11Ω, 22Ω, and 33Ω resistors are in parallel. That combination is in series with the 4Ω and 10Ω resistors.
The net resistance is:
R = 4Ω + 10Ω + 1/(1/11Ω + 1/22Ω + 1/33Ω)
R = 20Ω
Using Ohm's law, we can find the current going through the 4Ω and 10Ω resistors:
V = IR
120 V = I (20Ω)
I = 6 A
So the voltage drops are:
V = (4Ω) (6A) = 24 V
V = (10Ω) (6A) = 60 V
That means the voltage drop across the 11Ω, 22Ω, and 33Ω resistors is:
V = 120 V − 24 V − 60 V
V = 36 V
So the currents are:
I = 36 V / 11 Ω = 3.27 A
I = 36 V / 22 Ω = 1.64 A
I = 36 V / 33 Ω = 1.09 A
If we wanted to, we could also show this using Kirchhoff's laws.
Frequency = (speed) / (wavelength)
Speed = 3 x 10⁸ m/s
Wavelength = 3 cm = 0.03 m
Frequency = (3 x 10⁸ m/s) / (0.03 m)
Frequency = (3 x 10⁸ / 0.03) (m / m-s)
Frequency = 1 x 10¹⁰ Hz (10 Gigahertz)
2 water molecules contain 4 hydrogen atoms and 2 oxygen atoms. a mile of water molecules contains 2 moles of hydrogen atoms and 1 mole of oxygen atoms !
hope this helped :)
Answer:
Earth's average surface gravity is about 9.8 meters per second per second. ... The Moon's surface gravity is weaker because it is far less massive than Earth. A body's surface gravity is proportional to its mass but inversely proportional to the square of its radius.
Explanation:
Answer:
(a) 23 m/s, -4 m/s²
(b) Speed is decreasing.
Explanation:
The velocity of the object is given as:
v(t) = 27 - t²
When t = 2 secs, velocity, v(2) becomes:
v(2) = 27 - (2)²
v(2) = 27 - 4
v(2) = 23 m/s
The acceleration is the first derivative of the velocity, dv/dt:
a(t) = dv(t)/dt = -2t
Acceleration after 2 secs, a(2) is:
a(2) = -2*2
a(2) = -4 m/s²
(b) When velocity and acceleration have opposite signs, it means that the velocity and acceleration are in opposite directions, hence, the object is slowing down.
In other words, the speed is decreasing.
