Put them in order to smallest to largest: centimeter, femtometer, kilometer, light year, meter, nanometer

Reto: Aníbal desea construir una carpa de base hexagonal de 1,40 m de altura. El vértice de la base es de 0,80m y la longitud de

Rudiy27

Answer:

1.- para cubrir la superficie lateral 4.32 metros²

2.- Area de la base 2.15 metros²

3.- Volumen 1 m³

4.- Area total 6.47 metros²

Explanation:

El área lateral sera calcular el area de seis triangulos iguales cuya base es

0.80 de base x 6 lados = 4.80 metros perimetro de la base

4.80 perimetro de base x 1.80 arista lateral / 2 = 4.32m2

Area de la base:

Perímetro x Apotema / 2

Siendo la Apotema la altura de los triangulos que componen un hexagono calculada utilizando el teorema de pitágoras:

$\sqrt{0.8^2 + (0.8/2)^2} = Apotema$

Apotema = 0.894427191

Area: 4.80 x 0.894427191 / 2 = 2.146625258

sumando el area de la base mas el area lateral se obtiene el area total

2.15 + 4.32 = 6.47 metros

Volumen de la pirámide:

Area de la Base x Altura / 3

2.15 x 1.40 / 3 = 1.00333 m3

3 0

3 years ago

The heating element of a coffeemaker operates at 120 V and carries a current of 4.50 A. Assuming the water absorbs all of the en

Bond [772]

Answer:

It will take 313.376 sec to raise temperature to boiling point

Explanation:

We have given that potential difference V = 120 Volt

Current i = 4.50 A

So resistance $R=\frac{V}{i}=\frac{120}{4.50}=26.666ohm$

Heat flow in resistor will be equal to $Q=i^2Rt$

It is given that this heat is used for boiling the water

Mass of the water = 0.525 kg = 525 gram

Specific heat of water 4.186 J/gram/°C

Initial temperature is given as 23°C

Boiling temperature of water = 100°C

So change in temperature = 100-23 = 77°C

Heat required to raise the temperature of water $Q=mc\Lambda T$

So $4.50^2\times 26.666\times t=525\times 4.186\times 77$

t = 313.376 sec

So it will take 313.376 sec to raise temperature to boiling point

5 0

3 years ago

Read 2 more answers

What did hegel and kant have in common? they both were determined to disprove marxist theory. they both thought that only histor

Ira Lisetskai [31]

Answer:

The two philosophers furthermore seem to share the same conception of the conditions of human freedom. For Hegel as well as Kant, a theory of morality and political right devoted to advancing the cause of freedom must require more than just the absence of obstacles preventing the satisfaction of our animal passions.

Explanation:

Hope that help ;)

8 0

1 year ago

A 2.40 cm × 2.40 cm square loop of wire with resistance 1.20×10−2 Ω has one edge parallel to a long straight wire. The near edge

Norma-Jean [14]

Answer:

current in loops is 52.73 μA

Explanation:

given data

side of square a = b = 2.40 cm = 0.024 m

resistance R = 1.20×10^−2 Ω

edge of the loop c = 1.20 cm = 0.012 m

rate of current = 120 A/s

to find out

current in the loop

solution

we know current formula that is

current = voltage / resistance .................a

so current = 1/R × d∅/dt

and we know here that

flux ∅ = ( μ×I×b / 2π ) × ln (a+c/c) ...............b

so

d∅/dt = ( μ×b / 2π ) × ln (a+c/c) × dI/dt ...........c

so from equation a we get here current

current = ( μ×b / 2πR ) × ln (a+c/c) × dI/dt

current = ( 4π× $10^{-7}$ ×0.024 / 2π(1.20× $10^{-2}$ ) × ln (0.024 + 0.012/0.012) × 120

solve it and we get current that is

current = 4 × $10^{-7}$ × 1.09861 × 120

current = 52.73 × $10^{-6}$ A

so here current in loops is 52.73 μA

8 0

3 years ago

A ball of 12 kg is attached to a string of 0.8 meter spun at 4

lesantik [10]

Answer:

240 N

Explanation:

6 0

3 years ago

Put them in order to smallest to largest: centimeter, femtometer, kilometer, light year, meter, nanometer​

Put them in order to smallest to largest: centimeter, femtometer, kilometer, light year, meter, nanometer