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elena-s [515]
3 years ago
8

Why do we use the metric system/US customary system

Chemistry
1 answer:
azamat3 years ago
8 0

Answer:

It's because to make sense money.

It's to measure how much money we make.

You might be interested in
Which terms are used to identify pure substances
Semenov [28]

Answer:

Color, odor, density, melting temperature, boiling temperature, and solubility are examples of physical properties. Physical properties can be used to identify a pure substance.

Explanation:

please mark brainliest! :)

and have a great day! :>

3 0
3 years ago
Read 2 more answers
Chem help please. i cant figure out this problem
xxTIMURxx [149]
11 a- ions would exist in the solution, they can carry charges.

B-solids that are neutral, they wouldn't conduct much of a current.
3 0
3 years ago
10. A "neutral atom" is one that has the same number of _______ and ______
Paladinen [302]

Answer:

Protons and Electrons

Explanation:

Protons are positively charged particles in an atom and electrons are negatively charged. These charges cancel out to make a neutral atom. For example, Carbon has 6 protons (+6) and 6 electrons (-6). 6 - 6 is 0, making it neutral.

8 0
3 years ago
Please answer this question
ZanzabumX [31]

Answer:

Is the fixed number of water molecules present in one formula unit of a substance

Explanation:

When copper sulphate is heated in a china dish, the blue colomed crystal changes to a white powder due to the removal of molecules of water of crystallization

6 0
3 years ago
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction 2 NO ( g
enyata [817]

Answer:

ΔG = -61.5 kJ/mol (<u>Spontaneous process</u>)

Explanation:

2 NO (g)  +  O₂  (g)   ⇄  2NO₂ (g)

Let's apply the thermodynamic formula to calculate the ΔG

ΔG = ΔG° + R .T . lnQ

We don't know if the gases are at equilibrium, that's why we apply Q (reaction quotient)

ΔG = - 69 kJ/mol + 8.31x10⁻³ kJ/K.mol . 298K . ln Q

How can we know Q? By the partial pressures (Qp)

P NO = 0.450atm

PO₂ = 0.1 atm

PNO₂ = 0.650 atm

Qp = [NO₂]² / [NO]² . [O₂]

Qp = 0.650² / 0.450² . 0.1 = 20.86

ΔG = - 69 kJ/mol + 8.31x10⁻³ kJ/K.mol . 298K . ln 20.86

ΔG = -61.5 kJ/mol (<u>Spontaneous process</u>)

5 0
3 years ago
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