So we know the number of moles of each compound. If we need to know the concentration we must know the number of moles that the compounds react with...
The element bromine is not a reddish-brown liquid. Liquid is the substance bromine.
M=DV
M=3.103 g/mL * 19.8 mL = 61.44 g
CH3 is the empirical formula for the compound.
A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.
The number of atom or moles in the compound is
1.17 g C X 1 mol of C / 12.011 g C = 0.097411 mol of C.
0.287 g H x 1 mol of H / 1 g H = 0.28474 mol H.
This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.
So we can represent the compound with the formula C0.974H0.284.
Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.
we can divide 0.284 by 0.0974.
0.284 / 0.0974 = 3.
So here, Carbon is one and hydrogen is 3.
We can write the above formula as a CH3.
Hence the empirical formula for the sample compound is CH3.
For a detailed study of the empirical formula refer given link brainly.com/question/13058832.
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Answer:
A.) False B.)False C.) True D.) False E.) False
Explanation:
Answer:
False- The number of electrons does not affect the type of element.
Explanation:
The adding/removing of protons is what changes the type of element. for example, if you have a molecule of Boron, which has 5 protons, and you add one proton, you will have created a carbon molecule with 6 protons. The number of protons of an element is its atomic number. Elements can have varying numbers of both electrons and neutrons without changing the type of element.
