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melisa1 [442]
3 years ago
6

If an atom has 11 protons and 13 neutrons what is it’s atomic number

Chemistry
1 answer:
Travka [436]3 years ago
5 0

Answer:

the atomic number is 11 and element is Sodium (Na)

Explanation:

Number of Protons = Number of Electrons = 11

Number of Neutrons = 13

Here, the Number of Protons and Number of Electrons is 11

So,

the atomic number is <em><u>11</u></em> and element is <em><u>Sodium </u></em><em><u>(</u></em><em><u>Na) </u></em>

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__Co + __F2 --&gt; __CoF3
Natalka [10]

Answer:

2Co + 3F2 --> 2CoF3

Explanation:

When balancing an equation we need to ensure that the products used equal the reactants produced. Hence to balance the equation we need 3 F2 molecules so we have 6F atoms in total. and since 1 Co molecule bonds to 3 F molecules. We are gonna need to 2 Co molecules.

8 0
3 years ago
Which neutral atom is isoelectronic with Mn+4?
astraxan [27]

Explanation:

scandium

MN+4 means Mn has lost 4 electron which makes it orbital look like that of scandium

5 0
4 years ago
it takes a slug 20 minutes to travel from the grass to the trash can a trip of 15 meters. how far could the slug travel in 60 mi
bekas [8.4K]

Answer:

45 meters

Explanation:

Did the math

6 0
3 years ago
A vessel of volume 22.4 dm3 contains 20 mol h2 and 1 mol n2 ad 273.15 k initially. All of the nitrogen reacted with sufficient h
NikAS [45]

Nitrogen combine with hydrogen to produce ammonia \text{NH}_3 at a 1:3:2 ratio:

\text{N}_2 \; (g) + 3 \;  \text{H}_2 \; (g) \leftrightharpoons 2\; \text{NH}_3 \; (g)

Assuming that the reaction has indeed proceeded to completion- with all nitrogen used up as the question has indicated. 3 \; \text{mol} of hydrogen gas would have been consumed while 2 \; \text{mol} of ammonia would have been produced. The final mixture would therefore contain

  • 17 \; \text{mol} of \text{H}_2 \; (g) and
  • 2 \; \text{mol} of \text{NH}_3 \; (g)

Apply the ideal gas law to find the total pressure inside the container and the respective partial pressure of hydrogen and ammonia:

  • \begin{array}{lll} P(\text{container}) &= & n \cdot R \cdot T / V \\ & = & (17 + 2) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=&  1.926 \times 10^{3} \; \text{kPa} \end{array}
  • \begin{array}{lll} P(\text{H}_2) &= & n \cdot R \cdot T / V \\ & = & (17) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=&  1.723 \times 10^{3} \; \text{kPa} \end{array}
  • \begin{array}{lll} P(\text{NH}_3) &= & n \cdot R \cdot T / V \\ & = & (2) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=&  2.037 \times 10^{2} \; \text{kPa} \end{array}
6 0
3 years ago
10 atoms of aluminum reacts with 6 molecules of oxygen gas to produce aluminum oxide. 4 Al + 3 O2 ––&gt; 2 Al2O3 What is the exc
Mrrafil [7]

The excess reactant is Aluminum.

<u>Explanation:</u>

We have to write the balanced equation as,

4 Al+ 3 O₂ → 2 Al₂O₃

According to the molar ratio 4: 3, from the given balanced equation, we can say that 4 atoms of Al reacted with 3 molecules of oxygen.

Given that 10 atoms of aluminum reacts with 6 molecules of oxygen, as per the ratio only 8 atoms of Aluminum is required to react with 6 molecules of oxygen, so excess reactant is Aluminum.

8 0
4 years ago
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