1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MA_775_DIABLO [31]
3 years ago
5

Disaccharides are joined by glycosidic bonds formed between the anomeric carbon on one monosaccharide and a hydroxyl ( − OH ) gr

oup of another monosaccharide. Identify the types of linkages in each of the three disaccharides. Only place three of the linkages.
Chemistry
1 answer:
Anastaziya [24]3 years ago
7 0

<u>Solution and Explanation</u>

<u>1. </u>OH group is present above the plane in monosaccharide 1. Carbon atoms in both the rings are numbered in such way that carbon behind the oxygen at the right hand is C1 in the both rings. Carbon 1 bonds to carbon 2 of the next monosaccharide. Hence, the glycosidic linkage between disaccharide is  \beta 1 \rightarrow 2 .

2. OH group is present above the plane in monosaccharide 1 while in ring 2 it is present below the plane. Carbon atoms in both the rings are numbered in such way that carbon behind the oxygen at the right hand is C1 in the both rings. Carbon 2 bonds to carbon 1 of the next monosaccharide. Hence, the glycosidic linkage between disaccharide is   \beta 2 \rightarrow \alpha 1.

3. OH group is present below the plane in below the plane in both the rings. Carbon atoms in both the rings are numbered in such way that carbon behind the oxygen at the right hand is C1 in the both rings. Carbon 1 bonds to carbon 4 of the next monosaccharide. Hence, the glycosidic linkage between disaccharide is \alpha 1 \rightarrow 4.

You might be interested in
What is the Molecular formula of a compound containing 63.53% Hydrogen, 8.24% Nitrogen, 28.23% Oxygen, and has a molecular mass
Sidana [21]
The molecular formula is H108NO3
7 0
2 years ago
MULTIPLE CHOICE QUESTION
7nadin3 [17]

Answer:

Shorter

Explanation:

As a wavelength increases in size, its frequency, and energy (E) decrease. From these equations, you may realize that as the frequency increases, the wavelength gets shorter. As the frequency decreases, the wavelength gets longer. There are two basic types of waves: mechanical and electromagnetic.

7 0
3 years ago
Which of the following elements has the lowest first ionizition energy ?
Hatshy [7]

Answer:

I think Mg is correct I am not sure

5 0
2 years ago
Read 2 more answers
Describe how you would separate rock salt to obtain salt crystals and pure dry sand.
USPshnik [31]

Answer:

Separating Sand and Salt

Probably the easiest method to separate the two substances is to dissolve salt in water, pour the liquid away from the sand, and then evaporate the water to recover the salt.

6 0
3 years ago
Read 2 more answers
Help me with these two please​
prohojiy [21]

Answer:

13.A

14.B?

on 14 i don't know

Explanation:

3 0
2 years ago
Read 2 more answers
Other questions:
  • how do you separate a heterogenous mixture that contains powdered sulfur, pebbles, powdered iron, sand, and magnesium sulfate??
    11·1 answer
  • What is the difference between an atom and an element
    15·1 answer
  • All molecules are compounds<br> True or false
    13·1 answer
  • Is a backpacking tent a structure of mass, frame, or shell?<br> Which one would it be?
    6·1 answer
  • What will you suggest to a person who is suffering from the problem of acidity after overeating?
    11·2 answers
  • Identify the compound with the lowest dipole moment. Identify the compound with the lowest dipole moment. CH3CH2CH3 CH3OCH3 CH3C
    12·1 answer
  • Do you think a mutation (created during reproduction) in one gene is likely to result in a new trait in an offspring? Why or why
    8·1 answer
  • A sample of Ar(g) is contained in a
    10·1 answer
  • Solve the following 2 questions below, involving elements and reactions. *
    8·2 answers
  • Which element is the most reactive?
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!