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Vinil7 [7]
3 years ago
12

Simplify -5(2x-7)-4x+5

Mathematics
2 answers:
ivanzaharov [21]3 years ago
7 0

Answer:

-14x+35

Step-by-step explanation:

-10x+35-4x+5

-14x+40

lakkis [162]3 years ago
4 0
The answer is -14x+40

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The point A(4, 2) is reflected over the point (-1,4) and it's image is point B. What
r-ruslan [8.4K]

Answer:

  B = (-6, 6)

Step-by-step explanation:

If M is the midpoint of AB, then ...

  B = 2M - A

  B = 2(-1, 4) -(4, 2) = (-2-4, 8-2)

  B = (-6, 6)

7 0
3 years ago
Graph the image of the given triangle under a dilation with a scale factor of 14 and center of dilation ​ (0, 0) ​ . To graph th
DochEvi [55]

Answer:

the begging explanation

Step-by-step explanation:

hope this helped

5 0
3 years ago
15/35 in simplest form
Aleksandr-060686 [28]
Find the GCF of 15 and 35
15=3*5
35=7*5
The Greatest Common Factor here is 5
Divide both the numerator and denominator by this value to get the simplest form.
15/5=3
35/5=7
Final answer: 3/7
5 0
3 years ago
Read 2 more answers
HELP PLEASE!!!
ch4aika [34]

Answer:

The population of Bear in 2050 is 4750000

Step-by-step explanation:

A) The exponential growth equation for bear is as follows -

dN/dT = rmax * N

Where dN/dT = change in population

rmax is the maximum rate of change

N = Base population

B) Here the per capita rate of increase (r) will always be a positive value irrespective of the and hence we will assume this population to be growing exponentially.

C) dN/dT = rmax * N

D) dN / 5 = 2.5 * 380,000

dN = 5*2.5 * 380000

= 4750000

8 0
3 years ago
Solve this query plzzz​
Olin [163]

Step-by-step explanation:

\frac{\sin \:4A}{\cos \:2A}  \times \frac{1 - \cos \:2A}{1 - \cos\:4A}   = \tan \:A \\  \\ LHS =  \frac{\sin \:4A}{\cos \:2A}  \times \frac{1 - \cos \:2A}{1 - \cos\:4A}   \\  \\  =  \frac{2\sin \:2A.\cos \:2A}{\cos \:2A}   \times  \frac{1 - (2 { \cos}^{2}A - 1) }{1 - (2 { \cos}^{2}2A - 1) } \\  \\  = 2\sin \:2A   \times  \frac{1 - 2 { \cos}^{2}A  +  1}{1 - 2 { \cos}^{2}2A  + 1 } \\  \\  = 2\sin \:2A   \times  \frac{2- 2 { \cos}^{2}A  }{2 - 2 { \cos}^{2}2A   } \\  \\   = 2\sin \:2A   \times  \frac{2(1 - { \cos}^{2}A)  }{2 (1-  { \cos}^{2}2A)   } \\  \\   = 2\sin \:2A   \times  \frac{1 - { \cos}^{2}A}{1-  { \cos}^{2}2A   } \\  \\     = 2\sin \:2A   \times  \frac{ { \sin}^{2}A}{{ \sin}^{2}2A   } \\  \\    = 2  \times  \frac{ { \sin}^{2}A}{{ \sin}2A   } \\  \\   = 2  \times  \frac{ { \sin}^{2}A}{{ 2\sin}A. \cos \:   A } \\  \\   = \frac{ { \sin}A}{ \cos \:   A }  \\  \\  = tan \: A \\  \\  = RHS \\

7 0
3 years ago
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