I was going to say that you would need to change the mixed numbers into an improper fraction but then I realized that they both have the same denominator (4), meaning that in this case if the whole number outside of the fraction is bigger than the one for the other then it’s greater than regardless.
6 is greater than 5, so
5¾<6¼
Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
Answer:
(-8,5)
Step-by-step explanation:
its what comes in between the two
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Answer:
Janies' monthly pocket money is $180.
Step-by-step explanation:
Janies' adjusted monthly pocket money:
Initial pocket money = $150
Ratio of new pocket money = 6:5
Let his new pocket money be represented by x,
x:$150 = 6:5
$150 x 6 = x (5)
$900 = 5x
x = 
x = $180
Therefore, Janies' monthly pocket money is $180.
