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lukranit [14]
3 years ago
5

One liter of oven-dry soil sampled from the Chorro Creek Ranch field requires 300 g of water to completely saturate it.

Engineering
1 answer:
torisob [31]3 years ago
8 0

Answer:

porosity=23.07%

x=5.974*10^9cm^3

Explanation:

One liter of oven-dry soil sampled from the Chorro Creek Ranch field requires 300 g of water to completely saturate it.

Calculate (a) its porosity, n, and (b) the volume of water required to saturate the top 20 cm of 1 hectare of the field.

-Porosity of a soil sample can be calculated in five ways but i shall use the formula below

porosity=\frac{volume of pore}{volume of total} *100%%

volume  pore volume of sample is equal to water volume used to saturate the soil

total volume=sample volume +pore volume

1L=1000cm^3

density of water=density=mass/volume

1g/cm^3=300g/volume

vol=300cm^3

total volume=300+1000

1300

porosity =(300/1300)*100%

porosity=23.07%

2. Recall that volume=area *height

1 hectare=1*10^9cm^2

the volume of soil sample=1*10^9cm^2*20cm

2*10^10cm^3

porosity=\frac{x}{x+2*10^{10} } *100%%

23%=x/(x+2*10^10)*100%

x=5.974*10^9cm^3

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Answer:

//Program was implemented using C++ Programming Language

// Comments are used for explanatory purpose

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{

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int first;

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first = n;

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first = first / 10;

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if(first == 3) // if first digit is 3

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//Check if n is palindrome

temp=n; // save the value of n in a temporary Variable

while(n>0)

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n=n/10;

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cout<<n<<" is a palindrome";

else

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}

Explanation:

The above code segments is a functional program that checks if a number that starts with digit 3 is Palindromic or not.

The program was coded using C++ programming language.

The main method of the program is omitted.

Comments were used for explanatory purpose.

8 0
3 years ago
In the circuit given below, R1 = 17 kΩ, R2 = 74 kΩ, and R3 = 5 MΩ. Calculate the gain 1formula58.mml when the switch is in posit
Elenna [48]

Answer:a

a) Vo/Vi = - 3.4

b) Vo/Vi = - 14.8

c) Vo/Vi = - 1000

Explanation:

a)

R1 = 17kΩ

for ideal op-amp

Va≈Vb=0 so Va=0

(Va - Vi)/5kΩ + (Va -Vo)/17kΩ = 0

sin we know Va≈Vb=0

so

-Vi/5kΩ + -Vo/17kΩ = 0

Vo/Vi = - 17k/5k

Vo/Vi = -3.4

║Vo/Vi ║ = 3.4    ( negative sign phase inversion)

b)

R2 = 74kΩ

for ideal op-amp

Va≈Vb=0 so Va=0

so

(Va-Vi)/5kΩ + (Va-Vo)74kΩ = 0

-Vi/5kΩ + -Vo/74kΩ = 0

Vo/Vi = - 74kΩ/5kΩ

Vo/Vi = - 14.8

║Vo/Vi ║ = 14.8  ( negative sign phase inversion)

c)

Also for ideal op-amp

Va≈Vb=0 so Va=0

Now for position 3 we apply nodal analysis we got at position 1

(Va - Vi)/5kΩ + (Va - Vo)/5000kΩ = 0           ( 5MΩ = 5000kΩ )

so

-Vi/5kΩ + -Vo/5000kΩ = 0

Vo/Vi = - 5000kΩ/5kΩ

Vo/Vi = - 1000

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3 years ago
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Answer:

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Explanation:

I hope it's help u :)

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<h3>The characteristics of an onStep.</h3>

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Read more on onStep here: brainly.com/question/25619349

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