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Ne4ueva [31]
3 years ago
5

If the resistance reading on a DMM'S meter face is to 22.5 ohms in the range selector switch is set to R X 100 range, what is th

e actual measure resistance of the circuit?
Engineering
1 answer:
klemol [59]3 years ago
5 0

Answer:

The answer is 2.25 kΩ

Explanation:

Solution

Given that:

The resistance reading on a DMM'S meter face = 22.5 ohms

The range selector switch = R * 100 range,

We now have to find the actual measure resistance of the circuit which is given below:

The actual measured resistance of the circuit is=R * 100

= 22.5 * 100

=2.25 kΩ

Hence the measured resistance of the circuit is 2.25 kΩ

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A 75 ! coaxial transmission line has a length of 2.0 cm and is terminated with a load impedance of 37.5 j75 !. If the relative p
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Answer:

4.26

Explanation:

The wavelength λ is given by:

\lambda=v/f=c/nf\\c=speed\ of\ light=3*10^8m/s,f=frequency=3*10^9Hz,n=permittivity=2.56\\\\\lambda=3*10^8/(2.56*3*10^9)=0.0625\ m\\

Phase constant (β) = 2π/λ

βl = 2π/λ × l

l = 2 cm = 0.02 m

βl = 2π/0.0625 × 0.02=2.01 rad = 115.3°

1 rad = 180/π degrees

Z_L=load\ impedance=37.5+j75\\\\Z_o=characteristic impedance = 75\ ohm\\\\\tilde {Z_L}=Z_L/Z_o=37.5+j75/75=0.5+j

\tilde {Z_{in}}=\frac{\tilde {Z_{L}}+jtan\beta l}{1+j\tilde {Z_{L}}tan\beta l}=\frac{0.5+j+jtan(115.2)}{1+j(0.5+j)tan(115.2)}=0.253-j0.274\\  \\Z_{in}=Z_o\tilde {Z_{in}}=75(0.253-j0.274)=19-j20.5\\\\\Gamma_L=\frac{Z_L-Z_0}{Z_L+Z_o}=\frac{37.5+j75-75}{37.5+j75+75}=0.62\angle 83^o\\\\\Gamma_{in}=\frac{Z_{in}-Z_0}{Z_{in}+Z_o}=\frac{19-j20.5-75}{19-j20.5+75}=0.62\angle -147^o\\\\VSWR=\frac{1+\rho}{1-\rho} =\frac{1+0.62}{1-0.62}=4.26

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In an ideal reheat cycle, steam is generated at 6.3 Mpa, 450 deg. C and partially expands to 0.84 Mpa. At this point, the steam
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The voltage in a series circuit is being increased from 12 volts to 24 volts.
Advocard [28]

Answer:

  • resistance (ohms) will stay the same
  • amps will double

Explanation:

Assuming linear circuit elements being operated within their ratings, ...

  • resistance (ohms) will stay the same
  • amps will double

For constant resistance, current is proportional to voltage. For a circuit in which resistance is not affected by voltage or temperature, the resistance will stay the same when voltage increases. Then the current will be proportional to the voltage.

__

<em>Additional comments</em>

In some circuits, resistance is a function of temperature. An incandescent light, for example, increases its resistance as its temperature goes up. When voltage is increased, resistance is increased according to the increased power dissipation. Current increases, but not proportionally to voltage.

Some other devices also exhibit this effect, but their resistance is designed to increase to a high enough level that overall circuit current actually decreases when voltage exceeds a certain threshold.

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What are some goals of NYFEA? Select three options.
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Answer:

developing agricultural leaders

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Ammonia enters the expansion valve of a refrigeration system at a pressure of 10 bar and a temperature of 24 C and exits at 1 ba
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Answer:

h_{1} = h_2} = 293.45 KJ/kg.

The quality of the refrigerant exiting the expansion valve is

x_{2}=0.193596.

Explanation:

Fluid given Ammonia.

Inlet 1:-

Temperature T_{1} = 24^{o} C.

Pressure P_{1} = 10 bar.

Exit 2:-

Pressure P_{2} = 1 bar.

Solution:-

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2 years ago
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