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3 years ago

33. An object with a mass of 2300g has a force of 6.2N applied to it. What is the resulting acceleration

Chemistry

1 answer:

slamgirl [31]3 years ago

5 0

Answer:

The formula

Explanation:

acceleration=force(N)÷mass

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What would you need to do to calculate the molality of 10 mol of NaCl in 200

Makovka662 [10]

It will be the second one

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3 years ago

The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when

tia_tia [17]

Answer : The cell potential for this reaction is 0.50 V

Explanation :

The given cell reactions is:

$Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)$

The half-cell reactions are:

Oxidation half reaction (anode): $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction (cathode): $Pb^{2+}+2e^-\rightarrow Pb$

First we have to calculate the cell potential for this reaction.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}$

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = $25^oC=273+25=298K$

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = +0.63 V

$E_{cell}$ = cell potential for the reaction = ?

$[Zn^{2+}]$ = 3.5 M

$[Pb^{2+}]$ = $2.0\times 10^{-4}M$

Now put all the given values in the above equation, we get:

$E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}$

$E_{cell}=0.50V$

Therefore, the cell potential for this reaction is 0.50 V

5 0

3 years ago

Which of these are physical changes in matter chech all that apply

serious [3.7K]

Answer:

a pencil being sharpened

freezing water

boiling water

Explanation:

a physical change doesn't change the chemical structure of an object. That is why the other 2 are wrong

6 0

3 years ago

Read 2 more answers

Silver nitrate solution reacts with calcium chloride solution according to the equation: 2 AgNO3 + CaCl2 → Ca(NO3)2 + 2 AgCl All

HACTEHA [7]

Answer:

14.33 g

Explanation:

Solve this problem based on the stoichiometry of the reaction.

To do that we need the molecular weight of the masses involved and then calculate the number of moles, find the limiting reagent and finally calculate the mass of AgCl.

2 AgNO₃ + CaCl₂ ⇒ Ca(NO₃)₂ + 2 AgCl

mass, g 6.97 6.39 ?

MW ,g/mol 169.87 110.98 143.32

mol =m/MW 0.10 0.06 0.10

From the table above AgNO₃ is the limiting reagent and we will produce 0.10 mol AgCl which is a mass :

0.10 mol x 143.32 g/mol = 14.33 g

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3 years ago

2. What is the mass of a car with a momentum of 10,000.00 kgm/s, traveling at 15.0 m/s?

Svetradugi [14.3K]

Answer:

666.67 kg is the mass of a car.

Explanation:

Momentum is defined as amount of motion possessed by the the moving body. It is mathematically calculated by multiplying mass into velocity by which object is moving.

$Momentum(P)=Mass(m)\times Velocity(v)$

Mass of the car = m =?

Velocity of the car = v = 15.0 m/s

Momentum of the car = P = 10,000.00 kgm/s

$m=\frac{P}{v}$

$m=\frac{ 10,000.00 kgm/s}{15.0 m/s}=666.67 kg$

666.67 kg is the mass of a car.

7 0

3 years ago